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Alternating Current PYQs · MHT CET · JEE Main · NEET

Power, Power Factor & Wattless Current

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Q1MHT CET 2026 · 17 APR · SHIFT 2Easy

Power, Power Factor & Wattless Current

In a series LCR circuit alternating e.m.f. and current are given by the equations V=V0sin⁡(ωt)V = V_0\sin(\omega t) and I=I0sin⁡(ωt+π3)I = I_0\sin\left(\omega t + \frac{\pi}{3}\right) respectively. The average power dissipated in the circuit over one cycle of a.c. is (cos⁡60∘=0.5)(\cos 60^\circ = 0.5)

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Answer: (d)

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Q2MHT CET 2026 · 11 APR · SHIFT 2Easy

Power, Power Factor & Wattless Current

In series LCR circuit, resistance is 18 Ω18\ \Omega and impedance 33 Ω33\ \Omega. An r.m.s. Voltage of 220220 V is applied across the circuit. The true power consumed in a c. circuit is

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Answer: (d)

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Q3MHT CET 2026 · 11 APR · SHIFT 1Easy

Power, Power Factor & Wattless Current

In an AC circuit E=50sin⁡(500t), I=600sin⁡(500t+π3) mAE = 50\sin(500t),\ I = 600\sin\left(500t + \frac{\pi}{3}\right)\text{ mA}. What is the power dissipated in the circuit? [cos⁡60∘=0.5\cos 60^\circ = 0.5]

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Answer: (c)

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Q4MHT CET 2026 · 13 MAY · SHIFT 2Easy

Power, Power Factor & Wattless Current

In an a.c. circuit, if the power factor changes from 0.50.5 to 0.250.25 then the increase in impedance is

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Answer: (a)

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Q5MHT CET 2026 · 11 APR · SHIFT 2Easy

Power, Power Factor & Wattless Current

In an a.c. circuit containing L, C and R in series, the ratio of apparent power to the true power is (Z= impedance of the circuit and R= resistance)

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Answer: (d)

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Q6JEE Main 2026 · 6 APR · SHIFT 1Easy

Power, Power Factor & Wattless Current

A LCR series circuit driven with Erms=90 VE_{rms} = 90\text{ V} at frequency fd=30 Hzf_{\text{d}} = 30\text{ Hz} has resistance R=80 ΩR = 80\ \Omega, an inductance with inductive reactance XL=20.0 ΩX_L = 20.0\ \Omega and capacitance with capacitive reactance XC=80.0 ΩX_C = 80.0\ \Omega. The power factor of the circuit is ______.

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Answer: (a)

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Q7MHT CET 2026 · 19 MAY · SHIFT 1Medium

Power, Power Factor & Wattless Current

An inductor of inductance LL and a resistor of resistance RR are joined in series and connected to an a.c. source of frequency ω\omega. The power dissipated in the circuit is

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Answer: (c)

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Q8MHT CET 2026 · 12 MAY · SHIFT 1Medium

Power, Power Factor & Wattless Current

An e.m.f. e=E0cos⁡ωte = E_0 \cos\omega t is applied to a circuit containing L, C and R in series where XL=4RX_L = 4R and XC=RX_C = R. The average power dissipated in the circuit is

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Answer: (a)

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Q9MHT CET 2026 · 19 APR · SHIFT 2Medium

Power, Power Factor & Wattless Current

In series LCR circuit R=10 ΩR = 10\ \Omega and impedance is 30 Ω30\ \Omega. An r.m.s. voltage 210210 V, is applied across the circuit. The true power consumed in AC circuit is

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Answer: (c)

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Q10MHT CET 2026 · 11 APR · SHIFT 1Medium

Power, Power Factor & Wattless Current

An inductor of reactance 100 Ω100\ \Omega, a capacitor of reactance 50 Ω50\ \Omega, and a resistor of resistance 50 Ω50\ \Omega are connected in series with an AC source of 1010 V, 5050 Hz. Average power dissipated by the circuit is ____

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Answer: (a)

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Q11MHT CET 2026 · 13 MAY · SHIFT 1Medium

Power, Power Factor & Wattless Current

For series LCR circuit, the current is observed to lead the applied voltage. An additional capacitor C1C_1 when joined with capacitor C, makes the power factor of the circuit unity. The capacitor C1C_1 must be connected in

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Answer: (c)

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Q12MHT CET 2026 · 18 APR · SHIFT 1Medium

Power, Power Factor & Wattless Current

An a.c. source is applied to a series LR circuit with XL=3RX_L = 3R and power factor is X1X_1. Now a capacitor with Xc=RX_c = R is added in series to LR circuit and power factor is X2X_2. The ratio X1X_1 to X2X_2 is

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Answer: (d)

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Q13MHT CET 2026 · 15 APR · SHIFT 1Medium

Power, Power Factor & Wattless Current

A series LCR circuit is connected to an a.c. source of 220220 V, 5050 Hz. The circuit contains a resistance R=80 ΩR = 80\ \Omega, an inductor of inductive reactance 70 Ω70\ \Omega and capacitor of capacitive reactance 130 Ω130\ \Omega. The power factor of the circuit is x10\frac{x}{10}. The value of x is

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Answer: (a)

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Q14MHT CET 2026 · 13 APR · SHIFT 2Medium

Power, Power Factor & Wattless Current

In a series LR circuit with XL=RX_L = R. Power factor is P1P_1. If a capacitor of capacitance CC with Xc=XLX_c = X_L is added to the circuit the power factor becomes P2P_2. The ratio of P1P_1 to P2P_2 will be:

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Answer: (b)

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Q15JEE Main 2026 · 24 JAN · SHIFT 1Medium

Power, Power Factor & Wattless Current

For the series LCR circuit connected with 220 V,50 Hz220\text{ V}, 50\text{ Hz} a.c source as shown in the figure, the power factor is α10\frac{\alpha}{10}. The value of α\alpha is ______.

Figure

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Answer: (c)

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Q16JEE Main 2026 · 4 APR · SHIFT 1Medium

Power, Power Factor & Wattless Current

An inductor of 10 mH, capacitor of 0.1 μF0.1\ \mu\text{F} and a resistor of 100 Ω100\ \Omega are connected in series across an a.ca.c power supply 220 V,70 Hz220\text{ V}, 70\text{ Hz}. The power factor of the given circuit is 0.5. The difference in the inductive reactance and capacitance reactance is 3α Ω\sqrt{3}\alpha\ \Omega. The value of α\alpha is ______.

Numerical answer type. Work it out, then open the answer.

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Answer: 100

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Q17MHT CET 2026 · 14 MAY · SHIFT 2Medium

Power, Power Factor & Wattless Current

An arc lamp requires a direct current of 1010 A at 9090 V to function. If it is connected to 220220 V (rms), 5050 Hz a.c. supply, the series inductor needed for it to work is nearly

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Answer: (b)

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Q18MHT CET 2025 · 26 APR · SHIFT 2Easy

Power, Power Factor & Wattless Current

In series LCR circuit R =18 Ω= 18\ \Omega and impedance is 30 Ω30\ \Omega. An rms voltage 210 V is applied across the circuit. The true power consumed in AC circuit is nearly

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Answer: (c)

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Q19MHT CET 2025 · 21 APR · SHIFT 1Easy

Power, Power Factor & Wattless Current

In LCR series circuit, R = 18 Ω\Omega and impedance 33 Ω33\ \Omega. An r.m.s. voltage of 220 V is applied across the circuit. The true power consumed in a.c. circuit is

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Answer: (c)

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Q20MHT CET 2025 · 26 APR · SHIFT 2Easy

Power, Power Factor & Wattless Current

In an a.c. circuit containing L,C,RL, C, R in series the ratio of true power to apparent power is ( Z=Z = impedance of the circuit and R is the resistance)

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Answer: (d)

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Q21MHT CET 2025 · 23 APR · SHIFT 2Easy

Power, Power Factor & Wattless Current

If the power factor changes from 0.5 to 0.25 because impedance changes from Z1Z_1 to Z2Z_2 then Z1=xZ2Z_1 = xZ_2. The value of x is (Resistance remains constant)

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Answer: (b)

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Q22JEE Main 2025 · 29 JAN · SHIFT 1Easy

Power, Power Factor & Wattless Current

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A): Choke coil is simply a coil having a large inductance but a small resistance. Choke coils are used with fluorescent mercury-tube fittings. If household electric power is directly connected to a mercury tube, the tube will be damaged.

Reason (R): By using the choke coil, the voltage across the tube is reduced by a factor (R/R2+ω2L2)\left(R/\sqrt{R^2 + \omega^2 L^2}\right), where ω\omega is frequency of the supply across resistor RR and inductor LL. If the choke coil were not used, the voltage across the resistor would be the same as the applied voltage. In the light of the above statements, choose the most appropriate answer from the options given below:

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Answer: (b)

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Q23MHT CET 2025 · 20 APR · SHIFT 2Medium

Power, Power Factor & Wattless Current

An e.m.f. e=E0cos⁡ωte = E_0 \cos\omega t is applied to a circuit containing L,CL, C and RR in series where XL=3RX_L = 3R and XC=RX_C = R. The average power dissipated in the circuit is

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Answer: (b)

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Q24MHT CET 2025 · 19 APR · SHIFT 2Medium

Power, Power Factor & Wattless Current

In an L−RL - R circuit, the inductive reactance is equal to 3\sqrt{3} times the resistance ' RR ' of the circuit. An e.m.f. E=E0sin⁡(ωt)E = E_0 \sin(\omega t) is applied to the circuit. The power consumed in the circuit is

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Answer: (c)

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Q25JEE Main 2025 · 7 APR · SHIFT 2Medium

Power, Power Factor & Wattless Current

An inductor of reactance 100 Ω100\ \Omega, a capacitor of reactance 50 Ω50\ \Omega, and a resistor of resistance 50 Ω50\ \Omega are connected in series with an AC source of 10 V,50 Hz10\text{ V}, 50\text{ Hz}. Average power dissipated by the circuit is ___________ W.

Numerical answer type. Work it out, then open the answer.

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Answer: 1

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Q26MHT CET 2025 · 25 APR · SHIFT 1Medium

Power, Power Factor & Wattless Current

The power factor of a CR circuit is 12\frac{1}{\sqrt{2}}, If the frequency of a.c. signal is halved, then the power factor of the circuit will become

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Answer: (b)

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Q27MHT CET 2025 · 22 APR · SHIFT 1Medium

Power, Power Factor & Wattless Current

When alternating current is passed through L−RL - R series circuit, the power factor is 32\frac{\sqrt{3}}{2} and R=50 ΩR = 50\ \Omega, then the value of L is

[cos⁡π6=32,sin⁡π6=12,tan⁡π6=13]\left[\cos\frac{\pi}{6} = \frac{\sqrt{3}}{2}, \sin\frac{\pi}{6} = \frac{1}{2}, \tan\frac{\pi}{6} = \frac{1}{\sqrt{3}}\right]

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Answer: (c)

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Q28MHT CET 2025 · 19 APR · SHIFT 2Medium

Power, Power Factor & Wattless Current

An a.c. source is applied to a series LR circuit with XL=3RX_L = 3R and power factor is X1X_1. Now a capacitor with Xc=RX_c = R is added in series to LR circuit and the power factor is X2X_2. The ratio X1X_1 to X2X_2 is

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Answer: (c)

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Q29MHT CET 2024 · 16 MAY · SHIFT 1Easy

Power, Power Factor & Wattless Current

In LCR series circuit, an alternating e.m.f. 'e' and current ' ii ' are given by equations e=160sin⁡(100t)e = 160\sin(100t) Volt and i=250sin⁡(100t+π3) mAi = 250\sin\left(100t + \frac{\pi}{3}\right)\text{ mA}. The average power dissipated in the circuit is

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Answer: (c)

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Q30MHT CET 2024 · 3 MAY · SHIFT 1Easy

Power, Power Factor & Wattless Current

In an ACAC circuit E=200sin⁡(50t)E = 200\sin(50t) volt and I=100sin⁡(50t+π3) mAI = 100\sin\left(50t + \frac{\pi}{3}\right)\text{ mA}. The power dissipated in the circuit is

(sin⁡30∘=cos⁡60∘=0.5sin⁡60∘=cos⁡30∘=3/2)\left(\begin{matrix}\sin 30^\circ = \cos 60^\circ = 0.5 \\ \sin 60^\circ = \cos 30^\circ = \sqrt{3}/2\end{matrix}\right)

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Answer: (d)

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Q31MHT CET 2024 · 2 MAY · SHIFT 1Easy

Power, Power Factor & Wattless Current

In an A.C. circuit, the potential difference ' VV ' and current 'I' are given respectively by V=100sin⁡(100t) V,I=100sin⁡(100t+π3) mAV = 100\sin(100t)\text{ V}, I = 100\sin\left(100t + \frac{\pi}{3}\right)\text{ mA} The power dissipated in the circuit will be [Given →cos⁡π3=12\rightarrow \cos\frac{\pi}{3} = \frac{1}{2} ]

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Answer: (c)

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Q32JEE Main 2024 · 31 JAN · SHIFT 2Easy

Power, Power Factor & Wattless Current

An AC voltage V=20sin⁡200πtV = 20\sin 200\pi t is applied to a series LCR circuit which drives a current I=10sin⁡(200πt+π3)I = 10\sin\left(200\pi t + \frac{\pi}{3}\right). The average power dissipated is:

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Answer: (d)

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Q33JEE Main 2024 · 29 JAN · SHIFT 2Easy

Power, Power Factor & Wattless Current

In an a.c. circuit, voltage and current are given by:

V=100sin⁡(100t) VV = 100\sin(100t)\text{ V} and I=100sin⁡(100t+π3) mAI = 100\sin\left(100t + \frac{\pi}{3}\right)\text{ mA} respectively.

The average power dissipated in one cycle is:

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Answer: (c)

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Q34JEE Main 2024 · 27 JAN · SHIFT 2Easy

Power, Power Factor & Wattless Current

A series LCR circuit with L=100π mH,C=10−3π FL = \frac{100}{\pi}\text{ mH}, C = \frac{10^{-3}}{\pi}\text{ F} and R=10 ΩR = 10\ \Omega, is connected across an ac source of 220 V,50 Hz220\text{ V}, 50\text{ Hz} supply. The power factor of the circuit would be ________.

Numerical answer type. Work it out, then open the answer.

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Answer: 1

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Q35MHT CET 2024 · 9 MAY · SHIFT 1Easy

Power, Power Factor & Wattless Current

Average power associated with an ideal inductor and ideal capacitor over a complete cycle of a.c. is respectively

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Answer: (c)

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Q36MHT CET 2024 · 10 MAY · SHIFT 1Medium

Power, Power Factor & Wattless Current

An e.m.f. E=E0cos⁡ωtE = E_0 \cos\omega t is applied to the L−RL - R circuit. The inductive reactance is equal to the resistance ' RR ' of the circuit. The power consumed in the circuit is

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Answer: (c)

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Q37MHT CET 2024 · 9 MAY · SHIFT 2Medium

Power, Power Factor & Wattless Current

An e.m.f. E=E0cos⁡ωtE = E_0 \cos\omega t is applied to circuit containing L and R in series. If XL=2RX_L = 2R, then the power dissipated in the circuit is

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Answer: (b)

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Q38JEE Main 2024 · 9 APR · SHIFT 2Medium

Power, Power Factor & Wattless Current

A capacitor of reactance 43 Ω4\sqrt{3}\ \Omega and a resistor of resistance 4 Ω4\ \Omega are connected in series with an ac source of peak value 82 V8\sqrt{2}\text{ V}. The power dissipation in the circuit is __________ W.

Numerical answer type. Work it out, then open the answer.

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Answer: 4

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Q39JEE Main 2024 · 4 APR · SHIFT 2Medium

Power, Power Factor & Wattless Current

Match List I with List II

Figure

Choose the correct answer from the options given below:

LIST ILIST II
A.Purely capacitive circuitI.
B.Purely inductive circuitII.
C.LCR series at resonanceIII.
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Answer: (b)

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Q40JEE Main 2024 · 30 JAN · SHIFT 1Medium

Power, Power Factor & Wattless Current

A series L.R circuit connected with an ac source E=(25sin⁡1000t) VE = (25\sin 1000t)\text{ V} has a power factor of 12\frac{1}{\sqrt{2}}. If the source of emf is changed to E=(20sin⁡2000t) VE = (20\sin 2000t)\text{ V}, the new power factor of the circuit will be:

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Answer: (c)

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Q41MHT CET 2023 · 9 MAY · SHIFT 1Easy

Power, Power Factor & Wattless Current

In an ACAC circuit, the current is i=5sin⁡(100t−π2) Ai = 5\sin\left(100t - \frac{\pi}{2}\right)\text{ A} and voltage is e=200sin⁡(100t)e = 200\sin(100t) volt. Power consumption in the circuit is (cos⁡90∘=0)(\cos 90^\circ = 0)

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Answer: (b)

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Q42MHT CET 2023 · 14 MAY · SHIFT 1Easy

Power, Power Factor & Wattless Current

For a purely inductive or a purely capacitive circuit, the power factor is

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Answer: (a)

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Q43NEET 2023Easy

Power, Power Factor & Wattless Current

The maximum power is dissipated for an ac in a/an:

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Answer: (a)

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Q44JEE Main 2023 · 10 APR · SHIFT 1Easy

Power, Power Factor & Wattless Current

Given below are two statements:

Statement I: Maximum power is dissipated in a circuit containing an inductor, a capacitor and a resistor connected in series with an AC source, when resonance occurs

Statement II: Maximum power is dissipated in a circuit containing pure resistor due to zero phase difference between current and voltage.

In the light of the above statements, choose the correct answer from the options given below:

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Answer: (d)

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Q45MHT CET 2023 · 14 MAY · SHIFT 2Easy

Power, Power Factor & Wattless Current

What will be the phase difference between virtual voltage and virtual current when current in the circuit is wattless?

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Answer: (c)

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Q46MHT CET 2023 · 13 MAY · SHIFT 2Medium

Power, Power Factor & Wattless Current

In a L-RL\text{-}R circuit the inductive reactance is equal to the resistance RR in the circuit. An emf E=E0cos⁡ωtE = E_0 \cos\omega t is applied to the circuit. The power consumed in the circuit is

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Answer: (b)

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Q47JEE Main 2023 · 25 JAN · SHIFT 2Medium

Power, Power Factor & Wattless Current

A series LCR circuit is connected to an AC source of 220 V, 50 Hz. The circuit contains a resistance R = 80Ω\Omega, an inductor of inductive reactance XL=70 ΩX_L = 70\ \Omega, and a capacitor of capacitive reactance XC=130 ΩX_C = 130\ \Omega. The power factor of circuit is x10\frac{x}{10}. The value of xx is:

Numerical answer type. Work it out, then open the answer.

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Answer: 8

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Q48MHT CET 2023 · 14 MAY · SHIFT 2Medium

Power, Power Factor & Wattless Current

The power factor of an R-L circuit is 12\frac{1}{\sqrt{2}}. If the frequency of ACAC is doubled the power factor will now be

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Answer: (b)

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Q49MHT CET 2023 · 10 MAY · SHIFT 1Medium

Power, Power Factor & Wattless Current

In a series LR circuit, XL=RX_L = R, power factor is P1P_1. If a capacitor of capacitance CC with XC=XLX_C = X_L is added to the circuit the power factor becomes P2P_2. The ratio of P1P_1 to P2P_2 will be

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Answer: (b)

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Q50JEE Main 2023 · 30 JAN · SHIFT 1Medium

Power, Power Factor & Wattless Current

In a series LR circuit with XL=RX_L = R, power factor P1. If a capacitor of capacitance C with XC=XLX_C = X_L is added to the circuit the power factor becomes P2. The ratio of P1 to P2 will be:

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Answer: (a)

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Q51JEE Main 2022 · 25 JUN · SHIFT 1Easy

Power, Power Factor & Wattless Current

If wattless current flows in the AC circuit, then the circuit is:

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Answer: (b)

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Q52JEE Main 2022 · 30 JUL · SHIFT 2Medium

Power, Power Factor & Wattless Current

In an A.C circuit, V & I are given by V=250sin⁡(100t)V = 250\sin(100t) volt and I=10sin⁡(100t+π3) AI = 10\sin\left(100t + \frac{\pi}{3}\right)\text{ A} respectively The power dissipated in the circuit is:

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Answer: (b)

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Q53JEE Main 2022 · 26 JUL · SHIFT 1Medium

Power, Power Factor & Wattless Current

In a series LRLR circuit XL=RX_L = R and power factor of the circuit is P1P_1. When capacitor with capacitance CC such that XL=XCX_L = X_C is put in series, the power factor becomes P2P_2. The ratio P1P2\frac{P_1}{P_2} is:

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Answer: (b)

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Q54JEE Main 2022 · 27 JUL · SHIFT 1Medium

Power, Power Factor & Wattless Current

To light, a 50 W,100 V50\text{ W}, 100\text{ V} lamp is connected, in series with a capacitor of capacitance 50πx μF\frac{50}{\pi\sqrt{x}}\ \mu F, with 200 V,50 Hz AC200\text{ V}, 50\text{ Hz AC} source. The value of xx will be ___________.

Numerical answer type. Work it out, then open the answer.

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Answer: 3

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Q55JEE Main 2022 · 28 JUN · SHIFT 1Difficult

Power, Power Factor & Wattless Current

An AC source is connected to an inductance of 100 mH, a capacitance of 100 μ\muF and a resistance of 120 Ω\Omega as shown in figure. The time in which the resistance having a thermal capacity 2 J/∘^\circC will get heated by 16∘^\circ C is _____________ s.

Figure

Numerical answer type. Work it out, then open the answer.

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Answer: 15

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Q56JEE Main 2021 · 18 MAR · SHIFT 2Easy

Power, Power Factor & Wattless Current

In a series LCR circuit, the inductive reactance (XL) is 10Ω\Omega and the capacitive reactance (XC) is 4Ω\Omega. The resistance (R) in the circuit is 6Ω\Omega. The power factor of the circuit is:

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Answer: (c)

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Q57JEE Main 2021 · 27 AUG · SHIFT 2Medium

Power, Power Factor & Wattless Current

An ac circuit has an inductor and a resistor of resistance R in series, such that XL = 3R. Now, a capacitor is added in series such that XC = 2R. The ratio of new power factor with the old power factor of the circuit is 5:x\sqrt{5}:x. The value of x is ___________.

Numerical answer type. Work it out, then open the answer.

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Answer: 1

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Q58JEE Main 2021 · 25 JUL · SHIFT 2Difficult

Power, Power Factor & Wattless Current

Two circuits are shown in the figure (a) & (b). At a frequency of ____________ rad/s the average power dissipated in one cycle will be same in both the circuits.

Figure

Numerical answer type. Work it out, then open the answer.

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Answer: 500

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Q59JEE Main 2021 · 26 AUG · SHIFT 1Difficult

Power, Power Factor & Wattless Current

A series LCR circuit driven by 300 V at a frequency of 50 Hz contains a resistance R = 3 kΩ\Omega, an inductor of inductive reactance XL = 250 π Ω\pi\ \Omega and an unknown capacitor. The value of capacitance to maximize the average power should be: (Take π\pi2 = 10)

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Answer: (a)

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Q60JEE Main 2021 · 25 FEB · SHIFT 2Difficult

Power, Power Factor & Wattless Current

An LCR circuit contains resistance of 110Ω\Omega and a supply of 220 V at 300 rad/s angular frequency. If only capacitance is removed from the circuit, current lags behind the voltage by 45∘^\circ. If on the other hand, only inductor is removed the current leads by 45∘^\circ with the applied voltage. The rms current flowing in the circuit will be:

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Answer: (c)

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Q61JEE Main 2020 · 3 SEP · SHIFT 1Difficult

Power, Power Factor & Wattless Current

A 750 Hz, 20 V (rms) source is connected to a resistance of 100 Ω\Omega, an inductance of 0.1803 H and a capacitance of 10 μ\muF all in series. The time in which the resistance (heat capacity 2 J/oC) will get heated by 10oC. (assume no loss of heat to the surroudnings) is close to:

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Answer: (a)

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Q62JEE Main 2020 · 6 SEP · SHIFT 2Difficult

Power, Power Factor & Wattless Current

In a series LR circuit, power of 400W is dissipated from a source of 250 V, 50 Hz. The power factor of the circuit is 0.8. In order to bring the power factor to unity, a capacitor of value C is added in series to the L and R. Taking the value of C as (n3π)μ\left(\frac{n}{3\pi}\right)\muF, then value of n is __________.

Numerical answer type. Work it out, then open the answer.

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Answer: 400

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Q63JEE Main 2019 · 9 JAN · SHIFT 2Difficult

Power, Power Factor & Wattless Current

A series AC circuit containing an inductor (20 mH), a capacitor (120 μ\muF) and a resistor (60 Ω\Omega) is driven by an AC source of 24V/50 Hz. The energy dissipated in the circuit in 60 s is:

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Answer: (c)

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Q64NEET 2018Medium

Power, Power Factor & Wattless Current

An inductor 20 mH, a capacitor 100 μ\muF and a resistor 50 Ω\Omega are connected in series across a source of emf, V = 10 sin 314 t. The power loss in the circuit is

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Answer: (a)

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Q65JEE Main 2018Medium

Power, Power Factor & Wattless Current

In an a.c. circuit, the instantaneous e.m.f. and current are given by

e = 100 sin 30 t

i = 20 sin (30t−π4)\left(30t - \frac{\pi}{4}\right)

In one cycle of a.c., the average power consumed by the circuit and the wattless current are, respectively

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Answer: (c)

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Q66NEET 2016 · PHASE 2Easy

Power, Power Factor & Wattless Current

The potential differences across the resistance, capacitance and inductance are 80 V, 40 V and 100 V respectively in an L-C-R circuit. The power factor of this circuit is

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Answer: (c)

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Q67NEET 2016 · PHASE 1Medium

Power, Power Factor & Wattless Current

An inductor 20 mH, a capacitor 50 μF\mu F and a resistor 40 Ω\Omega are connected in series across a source of emf V = 10 sin 340t. The power loss in A.C. circuit is

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Answer: (c)

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Q68JEE Main 2016Medium

Power, Power Factor & Wattless Current

An arc lamp requires a direct current of 10 A at 80 V to function. If it is connected to a 220 V (rms), 50 Hz AC supply, the series inductor needed for it to work is close to:

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Answer: (b)

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Q69NEET 2015 · AIPMT · CANCELLED PAPERMedium

Power, Power Factor & Wattless Current

A resistance 'R' draws power 'P' when connected to an AC source. If an inductance is now placed in series with the resistance, such that the impedance of the circuit becomes 'Z'. the power drawn will be

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Answer: (c)

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Q70JEE Main 2015 · 11 APR · SHIFT 1Medium

Power, Power Factor & Wattless Current

For the LCR circuit, shown here, the current is observed to lead the applied voltage. An additional capacitor C', when joined with the capacitor C present in the circuit, makes the power factor of the circuit unity. The capacitor C', must have been connected in:

Figure

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Answer: (d)

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Q71JEE Main 2013 · 25 APR · SHIFT 1Difficult

Power, Power Factor & Wattless Current

A series LR circuit is connected to an ac source of frequency ω\omega and the inductive reactance is equal to 2R. A capacitance of capacitive reactance equal to R is added in series with L and R. The ratio of the new power factor to the old one is:

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Answer: (d)

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Q72NEET 2012 · AIPMT · MAINSEasy

Power, Power Factor & Wattless Current

The instantaneous values of alternating current and voltage in a circuit are given as i=12i = \frac{1}{\sqrt{2}} sin (100 π\pit) ampere

e=12sin⁡(100πt+π3)e = \frac{1}{\sqrt{2}}\sin\left(100\pi t + \frac{\pi}{3}\right) Volt

The average power in watts consumed in the circuit is

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Answer: (d)

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Q73JEE Main 2010 · AIEEEDifficult

Power, Power Factor & Wattless Current

In a series LCRLCR circuit R=200 ΩR = 200\ \Omega and the voltage and the frequency of the main supply are 220 V220\text{ V} and 50 Hz50\text{ Hz} respectively. On taking out the capacitance from the circuit the current lags behind the voltage by 30∘.30^\circ. On taking out the inductor from the circuit the current leads the voltage by 30∘.30^\circ. The power dissipated in the LCRLCR circuit is

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Answer: (d)

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Q74NEET 2009 · AIPMTEasy

Power, Power Factor & Wattless Current

Power dissipated in an LCR series circuit connected to an A.C. source of emf ε\varepsilon is

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Answer: (d)

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Q75NEET 2008 · AIPMTEasy

Power, Power Factor & Wattless Current

In an a.c. circuit the e.m.f. (ε\varepsilon) and the current

(i) at any instant are given respectively by

ε\varepsilon = E0sinω\omegat, i=Ii = I0sin(ω\omegat −ϕ-\phi)

The average power in the circuit over one cycle of a.c. is

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Answer: (a)

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Q76JEE Main 2007 · AIEEEEasy

Power, Power Factor & Wattless Current

In an a.c.\text{a.c.} circuit the voltage applied is E=E0sin⁡ωt.E = E_0\sin\omega t. The resulting current in the circuit is I=I0sin⁡(ωt−π2).I = I_0\sin\left(\omega t - \frac{\pi}{2}\right). The power consumption in the circuit is given by

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Answer: (c)

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Q77NEET 2006 · AIPMTMedium

Power, Power Factor & Wattless Current

A coil of inductive reactance 31 Ω\Omega has a resistance of 8 Ω\Omega. It is placed in series with a condenser of capacitative reactance 25 Ω\Omega. The combination is connected to an a.c. source of 110 V. The power factor of the circuit is

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Answer: (d)

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Q78JEE Main 2005 · AIEEEEasy

Power, Power Factor & Wattless Current

A circuit has a resistance of 12 ohm12\ \text{ohm} and an impedance of 15 ohm15\ \text{ohm}. The power factor of the circuit will be

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Answer: (b)

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Q79NEET 2002 · AIPMTEasy

Power, Power Factor & Wattless Current

For a series LCR circuit the power loss at resonance is

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Answer: (c)

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Q80JEE Main 2002 · AIEEEEasy

Power, Power Factor & Wattless Current

The power factor of ACAC circuit having resistance (R)(R) and inductance (L)(L) connected in series and an angular velocity ω\omega is

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Answer: (b)

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Q81NEET 1997 · AIPMTEasy

Power, Power Factor & Wattless Current

In an a.c. circuit with phase voltage VV and current II, the power dissipated is

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Answer: (b)

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Q82NEET 1995 · AIPMTEasy

Power, Power Factor & Wattless Current

In an A.C. circuit, the current flowing is I=5sin⁡(100t−π/2)I = 5\sin(100t - \pi/2) ampere and the potential difference is V=200sin⁡(100t)V = 200\sin(100t) volts. The power consumption is equal to

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Answer: (b)

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