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Gravitation PYQs · MHT CET · JEE Main · NEET

Newton's Law of Gravitation

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Q1JEE Main 2026 · 22 JAN · SHIFT 1Medium

Newton's Law of Gravitation

Net gravitational force at the center of a square is found to be F1F_1 when four particles having mass M,2M,3MM, 2M, 3M and 4M4M are placed at the four corners of the square as shown in figure and it is F2F_2 when the positions of 3M3M and 4M4M are interchanged. The ratio F1F2\frac{F_1}{F_2} is α5\frac{\alpha}{\sqrt{5}}. The value of α\alpha is ______.

Figure

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Answer: (a)

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Q2JEE Main 2025 · 3 APR · SHIFT 1Difficult

Newton's Law of Gravitation

Three identical spheres of mass m, are placed at the vertices of an equilateral triangle of length aa. When released, they interact only through gravitational force and collide after a time T=4T = 4 seconds. If the sides of the triangle are increased to length 2a2a and also the masses of the spheres are made 2 m, then they will collide after__________seconds.

Numerical answer type. Work it out, then open the answer.

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Answer: 8

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Q3JEE Main 2025 · 22 JAN · SHIFT 1Difficult

Newton's Law of Gravitation

A small point of mass mm is placed at a distance 2R2R from the centre ' OO ' of a big uniform solid sphere of mass M and radius R. The gravitational force on ' m ' due to M is F1F_1. A spherical part of radius R/3R/3 is removed from the big sphere as shown in the figure and the gravitational force on m due to remaining part of MM is found to be F2F_2. The value of ratio F1:F2F_1 : F_2 is

Figure

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Answer: (b)

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Q4JEE Main 2024 · 31 JAN · SHIFT 1Medium

Newton's Law of Gravitation

Four identical particles of mass mm are kept at the four corners of a square. If the gravitational force exerted on one of the masses by the other masses is (22+132)Gm2L2\left(\frac{2\sqrt{2}+1}{32}\right)\frac{Gm^{2}}{L^{2}}, the length of the sides of the square is

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Answer: (a)

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Q5MHT CET 2024 · 3 MAY · SHIFT 2Medium

Newton's Law of Gravitation

Two identical metal spheres are kept in contact with each other, each having radius ' RR ' cm and ' ρ\rho ' is the density of material of metal spheres. The gravitational force ' FF ' of attraction between them is proportional to

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Answer: (b)

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Q6JEE Main 2024 · 4 APR · SHIFT 1Medium

Newton's Law of Gravitation

A metal wire of uniform mass density having length LL and mass MM is bent to form a semicircular arc and a particle of mass mm is placed at the centre of the arc. The gravitational force on the particle by the wire is:

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Answer: (d)

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Q7MHT CET 2023 · 9 MAY · SHIFT 1Easy

Newton's Law of Gravitation

A thin rod of length 'LL' is bent in the form of a circle. Its mass is 'MM'. What force will act on mass 'mm' placed at the centre of this circle?

( G=G = constant of gravitation)

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Answer: (a)

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Q8MHT CET 2023 · 10 MAY · SHIFT 2Medium

Newton's Law of Gravitation

A system consists of three particles each of mass 'm1m_1 ' placed at the corners of an equilateral triangle of side ' L3\frac{L}{3} ', A particle of mass 'm2m_2 ' is placed at the mid point of any one side of the triangle. Due to the system of particles, the force acting on m2m_2 is

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Answer: (d)

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Q9MHT CET 2023 · 13 MAY · SHIFT 1Medium

Newton's Law of Gravitation

If two identical spherical bodies of same material and dimensions are kept in contact, the gravitational force between them is proportional to RxR^{x}, where xx is non zero integer [Given: RR is radius of each spherical body]

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Answer: (b)

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Q10NEET 2022 · PHASE 1Easy

Newton's Law of Gravitation

Match List - I with List - II

Choose the correct answer from the options given below

List - IList - II
(a)Gravitational constant (G)(i)[L2T[L^{2}T −2]^{-2}]
(b)Gravitational potential energy(ii)[M[M −1L3T^{-1}L^{3}T −2]^{-2}]
(c)Gravitational potential(iii)[LT[LT −2]^{-2}]
(d)Gravitational intensity(iv)[ML2T[ML^{2}T −2]^{-2}]
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Answer: (b)

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Q11JEE Main 2022 · 28 JUN · SHIFT 2Easy

Newton's Law of Gravitation

Two objects of equal masses placed at certain distance from each other attracts each other with a force of F. If one-third mass of one object is transferred to the other object, then the new force will be:

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Answer: (c)

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Q12JEE Main 2022 · 27 JUN · SHIFT 1Easy

Newton's Law of Gravitation

Given below are two statements:

Statement I: The law of gravitation holds good for any pair of bodies in the universe. Statement II: The weight of any person becomes zero when the person is at the centre of the earth. In the light of the above statements, choose the correct answer from the options given below.

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Answer: (a)

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Q13JEE Main 2022 · 25 JUL · SHIFT 1Difficult

Newton's Law of Gravitation

Three identical particles A,BA, B and CC of mass 100 kg100\text{ kg} each are placed in a straight line with AB=BC=13 mAB = BC = 13\text{ m}. The gravitational force on a fourth particle PP of the same mass is FF, when placed at a distance 13 m13\text{ m} from the particle BB on the perpendicular bisector of the line ACAC. The value of FF will be approximately:

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Answer: (b)

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Q14JEE Main 2021 · 26 FEB · SHIFT 1Difficult

Newton's Law of Gravitation

Find the gravitational force of attraction between the ring and sphere as shown in the diagram, where the plane of the ring is perpendicular to the line joining the centres. If 8\sqrt{8}R is the distance between the centres of a ring (of mass 'm') and a sphere (mass 'M') where both have equal radius 'R'.

Figure

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Answer: (c)

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Q15JEE Main 2021 · 25 FEB · SHIFT 1Difficult

Newton's Law of Gravitation

A solid sphere of radius R gravitationally attracts a particle placed at 3R from its centre with a force F1. Now a spherical cavity of radius (R2)\left(\frac{R}{2}\right) is made in the sphere (as shown in figure) and the force becomes F2. The value of F1: F2 is

Figure

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Answer: (c)

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Q16JEE Main 2019 · 12 JAN · SHIFT 1Difficult

Newton's Law of Gravitation

A straight rod of length L extends from x = a to x = L + a. The gravitational force it exerts on a point mass 'm' at x = 0, if the mass per unit length of the rod is A + Bx2, is given by:

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Answer: (b)

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Q17JEE Main 2018 · 15 APR · SHIFT 1Difficult

Newton's Law of Gravitation

Take the mean distance of the moon and the sun from the earth to be 0.4×1060.4 \times 10^{6} km and 150×106150 \times 10^{6} km respectively. Their masses are 8×10228 \times 10^{22} kg and 2×10302 \times 10^{30} kg respectively. The radius of the earth is 64006400 km. Let ΔF1\Delta F_1 be the difference in the forces exerted by the moon at the nearest and farthest points on the earth and ΔF2\Delta F_2 be the difference in the force exerted by the sun at the nearest and farthest points on the earth. Then, the number closest to ΔF1ΔF2\frac{\Delta F_1}{\Delta F_2} is:

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Answer: (a)

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Q18NEET 2017Easy

Newton's Law of Gravitation

Two astronauts are floating in gravitational free space after having lost contact with their spaceship. The two will

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Answer: (a)

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Q19JEE Main 2014 · 11 APR · SHIFT 1Difficult

Newton's Law of Gravitation

From a sphere of mass M and radius R, a smaller sphere of radius R2\frac{R}{2} is carved out such that the cavity made in the original sphere is between its centre and the periphery. (See figure). For the configuration in the figure where the distance between the center of the original sphere and the removed sphere is 3R, the gravitational force between the two spheres is:

Figure

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Answer: (a)

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Q20JEE Main 2013 · 22 APR · SHIFT 1Difficult

Newton's Law of Gravitation

The change in the value of acceleration of earth towards sun, when the moon comes from the position of solar eclipse to the position on the other side of earth in line with sun is: (mass of the moon = 7.36×10227.36 \times 10^{22} kg, radius of the moon's orbit = 3.8×1083.8 \times 10^{8} m).

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Answer: (a)

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Q21NEET 2010 · AIPMT · MAINSMedium

Newton's Law of Gravitation

(1) Centre of gravity (C.G) of a body is the point at which the weight of the body acts (2) Centre of mass coincides with the centre of gravity if the earth is assumed to have infinitely large radius.

(3) To evaluate the gravitational field intensity due to any body at an external point, the entire mass of the body can be considered to be concentrated at its C.G.

(4) The radius of gyration of any body rotating about an axis is the length of the perpendicular dropped from the C.G. of the body to the axis.

Which one of the following pairs of statements is correct?

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Answer: (a)

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Q22NEET 2010 · AIPMT · PRELIMSMedium

Newton's Law of Gravitation

A man of 50 kg mass is standing in a gravity free space at a height of 10 m above the floor. He throws a stone of 0.5 kg mass downwards with a speed 2 m/s. When the stone reaches the floor, the distance of the man above the floor will be

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Answer: (b)

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Q23NEET 2003 · AIPMTEasy

Newton's Law of Gravitation

Two spheres of masses m and M are situated in air and the gravitational force between them is F. The space around the masses is now filled with a liquid of specific gravity 3. The gravitational force will now be

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Answer: (b)

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Q24JEE Main 2003 · AIEEEDifficult

Newton's Law of Gravitation

Two spherical bodies of mass MM and 5M5M & radii RR & 2R2R respectively are released in free space with initial separation between their centers equal to 12R12R. If they attract each other due to gravitational force only, then the distance covered by the smaller body just before collision is

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Answer: (c)

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