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Theory · Physics Circle Master Book

Fluid Dynamics

01
CONCEPT

Types of Flow, Reynolds Number & Continuity

In one line
Slow flow is orderly and fast flow breaks up. In steady flow, the same volume passes every section, so av = constant.
STREAMLINE

2.1.1 Streamline flow

ABC
Each element follows the one before it
  1. Each element follows the same path with the same velocity as the element before it at that point.
  2. A streamline is a path whose tangent at any point gives the direction of flow.
  3. Two streamlines cannot cross.
  4. Crowded streamlines mean larger velocity.
LAMINAR

2.1.2 Laminar and turbulent flow

  1. Laminar: liquid moves in layers that do not mix. Velocity stays below the critical velocity.
  2. Turbulent: above the critical velocity the motion becomes irregular.
  3. Most of the energy then goes into eddies, as beside a bridge pillar.
pillar
Eddies behind a pillar
CRITICAL VELOCITY

2.1.3 Critical velocity and Reynolds number

  1. Critical velocity: the speed up to which flow stays streamline.
  2. Reynolds number Rn is a pure number: inertial force per unit area ÷ viscous force per unit area.
Rn = ρvdη
vc = Rn ηρd
  1. d is the diameter of the tube.
  2. vc is directly proportional to η, and inversely proportional to ρ and d.
RnFlow
below 1000streamline (steady)
1000 to 2000unsteady, changing
above 2000turbulent
  1. Some books give 2000 and 3000 as the limits instead. MHT CET questions follow this table.
CONTINUITY

2.1.4 Equation of continuity

v₁v₂a₁a₂
Tube of varying cross-section
  1. Mass in per second = mass out per second.
a₁ρ₁v₁ = a₂ρ₂v₂
  1. For an incompressible liquid, ρ₁ = ρ₂.
a₁v₁ = a₂v₂  ⇒  av = constant  ⇒  a ∝ 1v
av
Area against speed: a hyperbola
  1. Circular pipe: v ∝ 1r² ∝ 1d².
  2. Several outlets: n a₂v₂ = a₁v₁ (spray gun, sprinkler).
  3. Rate of flow Q = av.
EXAMPLES

2.1.5 Everyday examples

  1. Hills: narrow, shallow river, faster water. Plains: wide, deep river, slower water.
  2. Water from a tap speeds up as it falls, so the stream becomes narrower.
JEE · NEET

Corner

Force of a jet on a wall
  1. Mass striking per second = ρAv.
  2. Force = rate of change of momentum.
F = ρAv² (water stopped)
  1. Water bouncing back at the same speed: F = 2ρAv².
Falling stream from a tap
v₁v₂A₁A₂
The stream narrows
v₂² = v₁² + 2gh  ·  A₁v₁ = A₂v₂
Practise PYQs on this topicTypes of Flow, Reynolds Number & Continuity · 22 questions with solutions
02
CONCEPT

Bernoulli’s Equation

In one line
For an ideal fluid in steady flow, pressure + potential + kinetic energy per unit volume stays constant.
ENERGY

2.2.1 Energy of a flowing fluid

PerPressurePotentialKinetic
totalPVmgh12mv²
unit massPρgh12v²
unit volumePρgh12ρv²
THEOREM

2.2.2 Bernoulli’s theorem

P₁P₂v₂v₁h₁h₂
Liquid pushed through a tube
  1. Conditions: incompressible, non-viscous, steady flow, no source or sink.
  2. Work done by pressure: W = (P₁ − P₂)V.
  3. This work raises the PE and KE: W = ΔU + ΔK.
P₁ + ρgh₁ + 12ρv₁² = P₂ + ρgh₂ + 12ρv₂²
P + ρgh + 12ρv² = constant
  1. It is conservation of mechanical energy for a moving fluid.
HEAD

2.2.3 Other forms

Pρ + gh + 12v² = constant
Pρg + h + v²2g = constant
  1. Pρg is pressure head, h is gravitational head, v²2g is velocity head.
HORIZONTAL

2.2.4 Horizontal pipe

  1. h is the same on both sides, so ρgh cancels.
P₁ − P₂ = 12ρ(v₂² − v₁²)
  1. Join this with continuity, a₁v₁ = a₂v₂.
  2. Narrow part: largest v, smallest P.
  3. Wide part: smallest v, largest P.
FLOW RATE

2.2.5 Pressure difference and flow rate

P₁ − P₂ = ρQ²2(1a₂² − 1a₁²)
VALVE

2.2.6 Closed pipe and valve

  1. Valve shut: v = 0, gauge reads P₁.
  2. Valve open: gauge falls to P₂.
v = √(2(P₁ − P₂)ρ)
Practise PYQs on this topicBernoulli's Equation · 25 questions with solutions
03
CONCEPT

Applications of Bernoulli’s Theorem

In one line
Everywhere it is the same story: fast fluid, low pressure, and the pressure difference pushes things.
BOATS

2.3.1 Two boats moving side by side

v largeP < P₀P₀P₀
Fast water between them
  1. Water between them moves faster than on the outer sides.
  2. Pressure between them falls, so they are pushed towards each other.
  3. Two hanging balls with an air stream between them also come closer.
AEROPLANE

2.3.2 Aeroplane wing

v large, P smallv small, P largelift
Air travels faster over the top
  1. Air above the wing moves faster than air below.
  2. The pressure difference gives an upward dynamic lift.
Lift = A × 12ρ(vup² − vdown²)
  1. Level flight: lift = weight.
  2. Use the total wing area.
  3. For a small difference: ΔP ≈ ρ v Δv.
ATOMISER

2.3.3 Atomiser

Lfast airlow P
Scent spray, paint gun, carburettor
  1. Piston blows high-speed air over the top of a tube dipped in the liquid.
  2. Low pressure there makes the liquid rise, and it leaves as fine drops.
ROOFS

2.3.4 Roofs in a wind storm

windv large, P < P₀P₀
Pressure inside is atmospheric
  1. Fast wind over the roof gives low pressure above it.
  2. Pressure inside stays P₀.
Fup = 12ρv² × A
MAGNUS

2.3.5 Magnus effect

ωabove: v + rω, P smallbelow: v − rω, P largeF
Spin changes the air speed above and below the ball
  1. A spinning ball curves from its usual path.
  2. Speeds of air above and below differ by the spin: v + rω and v − rω.
  3. The pressure difference gives the sideways force.
VENTURIMETER

2.3.6 Venturimeter

hv₁v₂a₁a₂
Pressure difference read as a height h
  1. Measures the rate of flow of a liquid in a pipe.
  2. Works on Bernoulli’s theorem.
  3. Pressure is lower at the narrow part.
P₁ − P₂ = hρg
V = a₁a₂ √(2hga₁² − a₂²)
JEE · NEET

Corner

Magnus effect, curving sideways
  1. Back-spin: the ball stays up longer and the pitch curves less.
  2. Top-spin: the force acts downwards and shortens the flight.
  3. Spin about a vertical axis: out-swing or in-swing.
Practise PYQs on this topicApplications of Bernoulli's Theorem · 10 questions with solutions
04
CONCEPT

Velocity of Efflux (Torricelli)

In one line
Liquid leaves a hole at depth h with the speed of a body falling freely through h: v = √(2gh).
TORRICELLI

2.4.1 Torricelli’s theorem

ρHhv = √(2gh)x
Hole at depth h below the free surface
  1. Bernoulli just inside and outside the hole, with both surfaces at P₀.
P₀ + hρg = P₀ + 12ρv²  ⇒  v = √(2gh)
  1. Independent of the nature of the liquid, the amount of liquid and the area of the hole.
  2. Rate of flow: Q = a√(2gh).
  3. h is the depth below the free surface.
v₁v₂v₃
Deeper hole, larger speed: v₁ < v₂ < v₃
  1. If extra pressure P acts on the surface: ½ρv² = P + hρg.
RANGE

2.4.2 Range on the ground

  1. Time to fall from height (H − h): t = √(2(H − h)g).
x = vt = 2√(h(H − h))
xmax = H at h = H2
HH/2
Largest range at h = H2
hhsame x
Holes equally far from the top and the bottom
  1. Range is the same for depth h and depth (H − h).
  2. If the vessel stands on a block, use the total height of the hole above the ground.
TWO HOLES

2.4.3 Equal flow from two holes

a₁√h₁ = a₂√h₂
  1. Square hole of side a: area a². Circular hole: area πr².
STEADY LEVEL

2.4.4 Level held steady

  1. Inflow = outflow: Q = a√(2gh), so h = Q²2ga².
FALL OF LEVEL

2.4.5 Rate of fall of level

  1. Continuity between tank and hole.
Adydt = A₀v
EMPTYING

2.4.6 Time to empty a tank

hyAA₀
Tank area A, hole area A₀
t = AA₀ √(2g) [√H − √H′]
tempty = AA₀ √(2Hg)
  1. t ∝ √H: four times the height takes twice the time.
JEE · NEET

Corner

Thrust on the tank
h
Two holes on opposite sides
  1. Each jet pushes the tank back with F = ρAv² = 2ρAg × depth.
net F = 2ρAg(h₂ − h₁)
Practise PYQs on this topicVelocity of Efflux (Torricelli) · 29 questions with solutions
EXAM-DAY CARD

Just see this before the exam

Fluid Dynamics
Rn = ρvdη
Reynolds
a₁v₁ = a₂v₂
continuity
P + ρgh + 12ρv²
Bernoulli
F = ½ρv²A
roof, lift
v = √(2gh)
efflux
xmax = H
range
FORMULA SHEET

Whole chapter on one page

Flow

Rn = ρvdη

vc = Rnηρd

< 1000 steady, > 2000 turbulent

Continuity

a₁v₁ = a₂v₂, Q = av

v ∝ 1r²

n holes: n a₂v₂ = a₁v₁

Bernoulli

P + ρgh + ½ρv² = constant

P₁ − P₂ = ½ρ(v₂² − v₁²)

v = √(2(P₁ − P₂)ρ)

Uses

Lift = A ½ρ(vu² − vd²)

Roof: F = ½ρv²A

Venturi: P₁ − P₂ = hρg

Efflux

v = √(2gh)

x = 2√(h(H − h))

xmax = H at h = H2

Tank

a₁√h₁ = a₂√h₂

t = AA₀√(2Hg)

t ∝ √H

TOP MISTAKES

Avoid these = easy marks

MISTAKE ✗

v ∝ r⁻¹ for continuity

Narrow part has more pressure

Efflux depth from the bottom

Rn with radius instead of diameter

CORRECT ✓

v ∝ {F("1","r²")}

Narrow part: largest v, smallest P

h is measured from the free surface

Rn = ρvdη, d = diameter