Surface Energy & Work Done

A soap bubble of radius $\frac{1}{\sqrt{\pi}}$ cm is expanded to radius $\frac{3}{\sqrt{\pi}}$ cm. Surface tension of soap is 25 dyne/cm. The work done during expansion in erg is

If $450$ erg of work is done in blowing a soap bubble of radius '$r$', the additional work required to be done to blow it to a radius equal to $3r$ is

One large soap bubble of diameter 'D' breaks into $64$ bubbles having surface tension 'T'. The change in surface energy is

A soap bubble of radius R is blown. After heating the solution, a second bubble of radius 2R is blown. The work required to blow the second bubble in comparison to that required for the first bubble is

The surface tension of a soap bubble is 0.03 N/m. The work done in increasing the diameter of bubble from 2 cm to 6 cm is $\alpha\pi \times 10^{-4}$ J. The value of $\alpha$ is _________. (Take $\pi = 3.14$)

The surface tension of a soap is $3.5 \times 10^{-2}\text{ N/m}$. The work required to increase the radius of a soap bubble from 1 cm to 2 cm is $\alpha \times 10^{-6}\text{ J}$. The value of $\alpha$ is ______.

$(\pi = 22/7)$

A soap bubble of surface tension $0.04\text{ N/m}$ is blown to a diameter of 7 cm. If $(15000 - x)\,\mu\text{J}$ of work is done in blowing it further to make its diameter 14 cm, then the value of $x$ is $\underline{\qquad}\ .\ (\pi = 22/7)$

A frame made up of metallic wire enclosing a surface area A is covered with a soap film. If the area of the frame of metallic wire is reduced by 25% the energy of the soap film will be changed by

A rectangular film of liquid is expanded from ($6$ cm $\times 5$ cm) to ($8$ cm $\times 9$ cm). If the work done is $4 \times 10^{-4}$ J, the surface tension of the liquid is

The amount of work done in blowing a soap bubble such that its diameter increases from 'd' to ' $D$ ' is ( $T =$ surface tension of solution)

The amount of work done in blowing a soap bubble such that its diameter increases from $d_1$ to $d_2$ is ( $T =$ surface tension of soap solution)

A rectangular film of liquid is expanded from $(5\text{ cm} \times 4\text{ cm})$ to $(7\text{ cm} \times 8\text{ cm})$. If the work done is $3 \times 10^{-4}\text{ J}$, the surface tension of the liquid is (nearly)

The work done in blowing a soap bubble of radius $R$ is $W_1$ at room temperature. Now the soap is heated. From the heated another soap bubble of radius 2 R is blown and the work done is $W_2$. Then

A soap bubble is blown to a diameter of $7\text{ cm}.\ 36960\text{ erg}$ of work is done in blowing it further. If surface tension of soap is 40 dyne/$\text{cm}$ then the new radius is ________ cm. Take $\left(\pi = \frac{22}{7}\right)$.

A water film is formed between two parallel wires of 10 cm length. The distance of 0.5 cm between the wires is increased by 1 mm. The work done in the process is (surface tension of water $= 72\text{ N/m}$)

Consider a soap film on a rectangular frame of wire of area $3 \times 3\text{ cm}^{2}$. If the area of the soap film is increased to $5 \times 5\text{ cm}^{2}$, the work done in the process will be (surface tension of soap is $2.5 \times 10^{-2}\text{ N/m})$

If work done in blowing a soap bubble of volume $V$ is $W$, then the work done in blowing the bubble of volume $2V$ from same soap is

A soap bubble of radius '$R$' is blown. After heating a solution, a second bubble of radius '$2R$' is blown. The work required to blow the $2$nd bubble in comparison to that required for the $1$st bubble is

The amount of energy required to form a soap bubble of radius $2\text{ cm}$ from a soap is nearly: (surface tension of soap $= 0.03\text{ N m}^{-1}$)

Surface tension of a soap bubble is $2.0 \times 10^{-2}\text{ N m}^{-1}$. Work done to increase the radius of soap bubble from $3.5\text{ cm}$ to $7\text{ cm}$ will be:

Take $\left[\pi = \frac{22}{7}\right]$

The surface tension of soap is $3.5 \times 10^{-2}\text{ N m}^{-1}$. The amount of work done required to increase the radius of soap bubble from $10\text{ cm}$ to $20\text{ cm}$ is _________ $\times 10^{-4}\text{ J}$.

$(\text{take } \pi = 22/7)$

A film of soap is formed between two straight parallel wires of length $10\text{ cm}$ each separated by $0.5\text{ cm}$. If their separation is increased by $1\text{ mm}$ while still maintaining their parallelism. How much work will have to be done?

(surface tension of $= 65 \times 10^{-2}\text{ N/m}$)

The work done in blowing a soap bubble of radius $R$ is '$W_1$' at room temperature. Now the soap is heated. From the heated another soap bubble of radius $2R$ is blown and the work done is '$W_2$'. Then

Work done in increasing the size of a soap bubble from radius of $3\text{ cm}$ to $5\text{ cm}$ in millijoule is nearly (surface tension of soap $= 0.03\text{ N m}^{-1}$)

If the work done in blowing a soap bubble of volume '$V$' is '$W$', then the work done in blowing a soap bubble of volume '$2V$' will be

The work done in blowing a soap bubble of volume '$V$' is '$W$'. The work required to blow a soap bubble of volume '$2V$' is [$T =$ surface tension of soap solution]

If the surface tension of a soap is $3 \times 10^{-2}\text{ N/m}$ then the work done in forming a soap film of $20\text{ cm} \times 5\text{ cm}$ will be

The work done in blowing a soap bubble of radius $R$ is $W$. The work done in blowing a bubble of radius $2R$ of the same soap is

A rectangular film of liquid is extended from (4 cm $\times$ 2 cm) to (5 cm $\times$ 4 cm). If the work done is 3 $\times$ 10$-$4 J, the value of the surface tension of the liquid is

Work done in increasing the size of a soap bubble from a radius of $3\text{ cm}$ to $5\text{ cm}$ is nearly (Surface tension of soap $= 0.03\text{ N m}^{-1},$