Q1 MHT CET 2026 · 19 MAY · SHIFT 2 Easy ☆
Scalar (Dot) Product · Dot product: value
A vector A ⃗ \vec{A} A of magnitude 7 2 7\sqrt{2} 7 2 unit, another vector B ⃗ \vec{B} B of magnitude 14 14 14 unit are inclined at an angle of 6 0 ∘ 60^\circ 6 0 ∘ . The magnitude of the scalar product ( A ⃗ ⋅ B ⃗ ) (\vec{A} \cdot \vec{B}) ( A ⋅ B ) is [ cos ( 60 ) ∘ = 1 2 ] \left[\cos(60)^\circ = \frac{1}{2}\right] [ cos ( 60 ) ∘ = 2 1 ]
(a) 49 2 49\sqrt{2} 49 2 (b) 7 2 7\sqrt{2} 7 2 (c) 14 2 14\sqrt{2} 14 2 (d) 9 2 9\sqrt{2} 9 2 Show answer and solution
Answer: (a)
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Q2 MHT CET 2026 · 19 MAY · SHIFT 1 Easy ☆
Scalar (Dot) Product · Dot product: value
In a vector p ⃗ \vec{p} p , 'x' and 'y' components have magnitudes 2 units and 5 units respectively. A vector q ⃗ \vec{q} q , along negative Y axis has magnitude of 3 units. Then p ⃗ ⋅ q ⃗ \vec{p} \cdot \vec{q} p ⋅ q is
(a) − 6 -6 − 6 (b) − 9 -9 − 9 (c) − 10 -10 − 10 (d) − 15 -15 − 15 Show answer and solution
Answer: (d)
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Q3 MHT CET 2026 · 13 MAY · SHIFT 2 Easy ☆
Scalar (Dot) Product · Perpendicular vectors
The vector P ⃗ = a i ^ + a j ^ + 3 k ^ \vec{P} = a\hat{i} + a\hat{j} + 3\hat{k} P = a i ^ + a j ^ + 3 k ^ and Q ⃗ = a i ^ − 2 j ^ − k ^ \vec{Q} = a\hat{i} - 2\hat{j} - \hat{k} Q = a i ^ − 2 j ^ − k ^ are perpendicular to each other. Then positive value of 'a a a ' is
(a) 3 3 3 (b) 4 4 4 (c) 9 9 9 (d) 13 13 13 Show answer and solution
Answer: (a)
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Q4 MHT CET 2026 · 12 MAY · SHIFT 1 Easy ☆
Scalar (Dot) Product · Perpendicular vectors
If A ⃗ = 5 i ^ + 2 j ^ \vec{A} = 5\hat{i} + 2\hat{j} A = 5 i ^ + 2 j ^ and B ⃗ = a i ^ + 3 j ^ \vec{B} = a\hat{i} + 3\hat{j} B = a i ^ + 3 j ^ are perpendicular to each other, the value of 'a' is
(a) − 6 5 \frac{-6}{5} 5 − 6 (b) 6 5 \frac{6}{5} 5 6 (c) 4 5 \frac{4}{5} 5 4 (d) − 4 5 \frac{-4}{5} 5 − 4 Show answer and solution
Answer: (a)
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Q5 MHT CET 2026 · 20 APR · SHIFT 2 Easy ☆
Scalar (Dot) Product · Perpendicular vectors
If two vectors A ⃗ = 4 i ^ + n j ^ + 2 k ^ \vec{A} = 4\hat{i} + n\hat{j} + 2\hat{k} A = 4 i ^ + n j ^ + 2 k ^ and B ⃗ = 2 i ^ + 2 j ^ − k ^ \vec{B} = 2\hat{i} + 2\hat{j} - \hat{k} B = 2 i ^ + 2 j ^ − k ^ are mutually perpendicular to each other then value of 'n' is
(a) + 3 +3 + 3 (b) + 1 +1 + 1 (c) − 3 -3 − 3 (d) − 1 -1 − 1 Show answer and solution
Answer: (c)
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Q6 MHT CET 2026 · 13 APR · SHIFT 1 Easy ☆
Scalar (Dot) Product · Perpendicular vectors
The vector sum of the two forces A ⃗ \vec{A} A and B ⃗ \vec{B} B is perpendicular to their vector difference. Hence forces A ⃗ \vec{A} A and B ⃗ \vec{B} B are
(a) perpendicular to each other (b) unequal in magnitude (c) parallel to each other (d) equal in magnitude Show answer and solution
Answer: (d)
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Q7 MHT CET 2026 · 11 APR · SHIFT 2 Easy ☆
Scalar (Dot) Product · Perpendicular vectors
The vectors ( A ⃗ + B ⃗ ) (\vec{A} + \vec{B}) ( A + B ) and ( A ⃗ − B ⃗ ) (\vec{A} - \vec{B}) ( A − B ) are perpendicular to each other. This is possible under the condition
(a) ∣ A ⃗ ∣ = ∣ B ⃗ ∣ |\vec{A}| = |\vec{B}| ∣ A ∣ = ∣ B ∣ (b) A ⃗ ⋅ B ⃗ = 0 \vec{A} \cdot \vec{B} = 0 A ⋅ B = 0 (c) A ⃗ × B ⃗ = 0 \vec{A} \times \vec{B} = 0 A × B = 0 (d) A ⃗ ⋅ B ⃗ = 1 \vec{A} \cdot \vec{B} = 1 A ⋅ B = 1 Show answer and solution
Answer: (a)
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Q8 MHT CET 2026 · 16 APR · SHIFT 2 Medium ☆
Scalar (Dot) Product · Perpendicular vectors
Vectors a i ^ + b j ^ + k ^ a\hat{i} + b\hat{j} + \hat{k} a i ^ + b j ^ + k ^ and 2 i ^ − 3 j ^ + 4 k ^ 2\hat{i} - 3\hat{j} + 4\hat{k} 2 i ^ − 3 j ^ + 4 k ^ are perpendicular to each other when 3 a + 2 b = 7 3a + 2b = 7 3 a + 2 b = 7 , the ratio of a to b is x / 2 x/2 x /2 . The value of x is
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Answer: (b)
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Q9 MHT CET 2026 · 13 APR · SHIFT 2 Medium ☆
Scalar (Dot) Product · Perpendicular vectors
Calculate the values of a a a and b b b if vectors a i ^ + b j ^ = n ^ a\hat{i} + b\hat{j} = \hat{n} a i ^ + b j ^ = n ^ and ( i ^ + j ^ ) (\hat{i} + \hat{j}) ( i ^ + j ^ ) are perpendicular to each other
(a) 1 2 , 1 2 \frac{1}{2}, \frac{1}{2} 2 1 , 2 1 (b) 0 , 0 0, 0 0 , 0 (c) 2 , − 1 2 \sqrt{2}, \ -\frac{1}{\sqrt{2}} 2 , − 2 1 (d) ( 1 2 ) , ( − 1 2 ) \left(\frac{1}{\sqrt{2}}\right), \left(-\frac{1}{\sqrt{2}}\right) ( 2 1 ) , ( − 2 1 ) Show answer and solution
Answer: (d)
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Q10 MHT CET 2025 · 22 APR · SHIFT 2 Easy ☆
Scalar (Dot) Product · Dot product: value
Given A ⃗ = ( 2 i ^ − 3 j ^ + k ^ ) , B ⃗ = ( 3 i ^ + j ^ − 2 k ^ ) \vec{A} = (2\hat{i} - 3\hat{j} + \hat{k}), \quad \vec{B} = (3\hat{i} + \hat{j} - 2\hat{k}) A = ( 2 i ^ − 3 j ^ + k ^ ) , B = ( 3 i ^ + j ^ − 2 k ^ ) and C ⃗ = ( 3 i ^ + 2 j ^ + k ^ ) \vec{C} = (3\hat{i} + 2\hat{j} + \hat{k}) C = ( 3 i ^ + 2 j ^ + k ^ ) , then ( A ⃗ + B ⃗ ) ⋅ C ⃗ (\vec{A} + \vec{B}) \cdot \vec{C} ( A + B ) ⋅ C will be
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Answer: (a)
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Q11 MHT CET 2025 · 22 APR · SHIFT 2 Easy ☆
Scalar (Dot) Product · Dot product: value
Given A ⃗ = ( 2 i ^ − 3 j ^ + k ^ ) , B ⃗ = ( 3 i ^ + j ^ − 2 k ^ ) \vec{A} = (2\hat{i} - 3\hat{j} + \hat{k}), \quad \vec{B} = (3\hat{i} + \hat{j} - 2\hat{k}) A = ( 2 i ^ − 3 j ^ + k ^ ) , B = ( 3 i ^ + j ^ − 2 k ^ ) and C ⃗ = ( 3 i ^ + 2 j ^ + k ^ ) \vec{C} = (3\hat{i} + 2\hat{j} + \hat{k}) C = ( 3 i ^ + 2 j ^ + k ^ ) , then ( A ⃗ + B ⃗ ) ⋅ C ⃗ (\vec{A} + \vec{B}) \cdot \vec{C} ( A + B ) ⋅ C will be
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Answer: (a)
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Q12 MHT CET 2025 · 26 APR · SHIFT 2 Easy ☆
Scalar (Dot) Product · Perpendicular vectors
The vector sum of two forces A ⃗ \vec{A} A and B ⃗ \vec{B} B is perpendicular to their vector difference. Hence forces A ⃗ \vec{A} A and B ⃗ \vec{B} B are
(a) perpendicular to each other. (b) parallel to each other. (c) unequal in magnitude. (d) equal in magnitude. Show answer and solution
Answer: (d)
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Q13 MHT CET 2025 · 5 MAY · SHIFT 2 Medium ☆
Scalar (Dot) Product · Perpendicular vectors
Two vectors a i ^ + b j ^ + k ^ a\hat{i} + b\hat{j} + \hat{k} a i ^ + b j ^ + k ^ and 2 i ^ − 3 j ^ + 4 k ^ 2\hat{i} - 3\hat{j} + 4\hat{k} 2 i ^ − 3 j ^ + 4 k ^ are perpendicular to each other. When 3 a + 2 b = 7 3a + 2b = 7 3 a + 2 b = 7 , the ratio of a a a to b b b is x 2 \frac{x}{2} 2 x . The value of x x x is
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Answer: (c)
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Q14 MHT CET 2025 · 23 APR · SHIFT 1 Medium ☆
Scalar (Dot) Product · Perpendicular vectors
If P ⃗ = b i ^ + 6 j ^ + k ^ \vec{P} = b\hat{i} + 6\hat{j} + \hat{k} P = b i ^ + 6 j ^ + k ^ and Q ⃗ = i ^ − a j ^ + 4 k ^ \vec{Q} = \hat{i} - a\hat{j} + 4\hat{k} Q = i ^ − a j ^ + 4 k ^ are perpendicular to each other, also 3 b − a = 5 3b - a = 5 3 b − a = 5 . The value of a a a and b b b is
(a) a = 2 , b = 10 a = 2, \ b = 10 a = 2 , b = 10 (b) a = 1 , b = 2 a = 1, \ b = 2 a = 1 , b = 2 (c) a = 2 , b = 3 a = 2, \ b = 3 a = 2 , b = 3 (d) a = 4 , b = 3 a = 4, \ b = 3 a = 4 , b = 3 Show answer and solution
Answer: (b)
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Q15 JEE Main 2025 · 23 JAN · SHIFT 1 Medium ☆
Scalar (Dot) Product · Perpendicular vectors
Two particles are located at equal distance from origin. The position vectors of those are represented by A ⃗ = 2 i ^ + 3 n j ^ + 2 k ^ \vec{A} = 2\hat{i} + 3n\hat{j} + 2\hat{k} A = 2 i ^ + 3 n j ^ + 2 k ^ and B ⃗ = 2 i ^ − 2 j ^ + 4 p k ^ \vec{B} = 2\hat{i} - 2\hat{j} + 4p\hat{k} B = 2 i ^ − 2 j ^ + 4 p k ^ , respectively. If both the vectors are at right angle to each other, the value of n − 1 n^{-1} n − 1 is ________.
Numerical answer type. Work it out, then open the answer.
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Answer: 3
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Q16 JEE Main 2023 · 24 JAN · SHIFT 2 Easy ☆
Scalar (Dot) Product · Perpendicular vectors
If two vectors P ⃗ = i ^ + 2 m j ^ + m k ^ \vec{P} = \hat{i} + 2m\hat{j} + m\hat{k} P = i ^ + 2 m j ^ + m k ^ and Q ⃗ = 4 i ^ − 2 j ^ + m k ^ \vec{Q} = 4\hat{i} - 2\hat{j} + m\hat{k} Q = 4 i ^ − 2 j ^ + m k ^ are perpendicular to each other. Then, the value of m will be:
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Answer: (d)
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Q17 JEE Main 2023 · 24 JAN · SHIFT 1 Medium ☆
Scalar (Dot) Product · Perpendicular vectors
Vectors a i ^ + b j ^ + k ^ a\hat{i} + b\hat{j} + \hat{k} a i ^ + b j ^ + k ^ and 2 i ^ − 3 j ^ + 4 k ^ 2\hat{i} - 3\hat{j} + 4\hat{k} 2 i ^ − 3 j ^ + 4 k ^ are perpendicular to each other when 3 a + 2 b = 7 3a + 2b = 7 3 a + 2 b = 7 , the ratio of a a a to b b b is x 2 \frac{x}{2} 2 x . The value of x x x is ____________.
Numerical answer type. Work it out, then open the answer.
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Answer: 1
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Q18 JEE Main 2022 · 28 JUL · SHIFT 1 Easy ☆
Scalar (Dot) Product · Angle & projection
If the projection of 2 i ^ + 4 j ^ − 2 k ^ 2\hat{i} + 4\hat{j} - 2\hat{k} 2 i ^ + 4 j ^ − 2 k ^ on i ^ + 2 j ^ + α k ^ \hat{i} + 2\hat{j} + \alpha\hat{k} i ^ + 2 j ^ + α k ^ is zero. Then, the value of α \alpha α will be ___________.
Numerical answer type. Work it out, then open the answer.
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Answer: 5
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Q19 JEE Main 2022 · 26 JUL · SHIFT 2 Easy ☆
Scalar (Dot) Product · Angle & projection
If A ⃗ = ( 2 i ^ + 3 j ^ − k ^ ) m \vec{A} = (2\hat{i} + 3\hat{j} - \hat{k})\text{ m} A = ( 2 i ^ + 3 j ^ − k ^ ) m and B ⃗ = ( i ^ + 2 j ^ + 2 k ^ ) m \vec{B} = (\hat{i} + 2\hat{j} + 2\hat{k})\text{ m} B = ( i ^ + 2 j ^ + 2 k ^ ) m . The magnitude of component of vector A ⃗ \vec{A} A along vector B ⃗ \vec{B} B will be ____________ m \text{m} m .
Numerical answer type. Work it out, then open the answer.
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Answer: 2
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Q20 JEE Main 2021 · 22 JUL · SHIFT 2 Easy ☆
Scalar (Dot) Product · Angle & projection
What will be the projection of vector A ⃗ = i ^ + j ^ + k ^ \vec{A} = \hat{i} + \hat{j} + \hat{k} A = i ^ + j ^ + k ^ on vector B ⃗ = i ^ + j ^ \vec{B} = \hat{i} + \hat{j} B = i ^ + j ^ ?
(a) 2 ( i ^ + j ^ + k ^ ) \sqrt{2}(\hat{i} + \hat{j} + \hat{k}) 2 ( i ^ + j ^ + k ^ ) (b) ( i ^ + j ^ ) (\hat{i} + \hat{j}) ( i ^ + j ^ ) (c) 2 ( i ^ + j ^ ) \sqrt{2}(\hat{i} + \hat{j}) 2 ( i ^ + j ^ ) (d) 2 ( i ^ + j ^ + k ^ ) 2(\hat{i} + \hat{j} + \hat{k}) 2 ( i ^ + j ^ + k ^ ) Show answer and solution
Answer: (b)
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Q21 MHT CET 2019 · 3 MAY · SHIFT 1 Easy ☆
Scalar (Dot) Product · Perpendicular vectors
The vectors ( A + B ) (\mathbf{A} + \mathbf{B}) ( A + B ) and ( A − B ) (\mathbf{A} - \mathbf{B}) ( A − B ) are at right angles to each other. This is possible under the condition
(a) ∣ A ∣ = ∣ B ∣ |A| = |B| ∣ A ∣ = ∣ B ∣ (b) A ⋅ B = 0 A \cdot B = 0 A ⋅ B = 0 (c) A ⋅ B = 1 A \cdot B = 1 A ⋅ B = 1 (d) A × B = 0 A \times B = 0 A × B = 0 Show answer and solution
Answer: (a)
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Q22 MHT CET 2019 · 2 MAY · SHIFT 2 Easy ☆
Scalar (Dot) Product · Angle & projection
P \mathbf{P} P and Q \mathbf{Q} Q are two non-zero vectors inclined to each other at an angle ' θ \theta θ '. ' p p p ' and ' q q q ' are unit vectors along P \mathbf{P} P and Q \mathbf{Q} Q respectively. The component of Q \mathbf{Q} Q in the direction of P \mathbf{P} P will be
(a) p ⋅ Q p \cdot Q p ⋅ Q (b) P × Q P \frac{P \times Q}{P} P P × Q (c) P ⋅ Q Q \frac{P \cdot Q}{Q} Q P ⋅ Q (d) p ⋅ q p \cdot q p ⋅ q Show answer and solution
Answer: (a)
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Q23 JEE Main 2019 · 8 APR · SHIFT 2 Difficult ☆
Scalar (Dot) Product · Dot product: value
Let ∣ A ⃗ 1 ∣ = 3 , ∣ A ⃗ 2 ∣ = 5 \left|\vec{A}_1\right| = 3, \ \left|\vec{A}_2\right| = 5 A 1 = 3 , A 2 = 5 and ∣ A ⃗ 1 + A ⃗ 2 ∣ = 5 \left|\vec{A}_1 + \vec{A}_2\right| = 5 A 1 + A 2 = 5 . The value of ( 2 A ⃗ 1 + 3 A ⃗ 2 ) ⋅ ( 3 A ⃗ 1 − 2 A ⃗ 2 ) \left(2\vec{A}_1 + 3\vec{A}_2\right) \cdot \left(3\vec{A}_1 - 2\vec{A}_2\right) ( 2 A 1 + 3 A 2 ) ⋅ ( 3 A 1 − 2 A 2 ) is :-
(a) –118.5 (b) –112.5 (c) –99.5 (d) –106.5 Show answer and solution
Answer: (a)
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Q24 JEE Main 2018 · 16 APR · SHIFT 1 Difficult ☆
Scalar (Dot) Product · Perpendicular vectors
Let A ⃗ = ( i ^ + j ^ ) \vec{A} = (\hat{i} + \hat{j}) A = ( i ^ + j ^ ) and, B ⃗ = ( 2 i ^ − j ^ ) . \vec{B} = (2\hat{i} - \hat{j}). B = ( 2 i ^ − j ^ ) . The magnitude of a coplanar vector C ⃗ \vec{C} C such that A ⃗ ⋅ C ⃗ = B ⃗ ⋅ C ⃗ = A ⃗ ⋅ B ⃗ , \vec{A} \cdot \vec{C} = \vec{B} \cdot \vec{C} = \vec{A} \cdot \vec{B}, A ⋅ C = B ⋅ C = A ⋅ B , is given by:
(a) 10 9 \sqrt{\frac{10}{9}} 9 10 (b) 5 9 \sqrt{\frac{5}{9}} 9 5 (c) 20 9 \sqrt{\frac{20}{9}} 9 20 (d) 9 12 \sqrt{\frac{9}{12}} 12 9 Show answer and solution
Answer: (b)
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