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Vectors PYQs · MHT CET · JEE Main · NEET

Vector (Cross) Product

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MHT CET
7
JEE Main
7
NEET
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Q1MHT CET 2026 · 20 APR · SHIFT 1Medium

Vector (Cross) Product

The area of parallelogram formed by vectors P⃗=2i^−j^+5k^\vec{P} = 2\hat{i} - \hat{j} + 5\hat{k} and Q⃗=3i^−2j^+4k^\vec{Q} = 3\hat{i} - 2\hat{j} + 4\hat{k} is

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Answer: (b)

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Q2MHT CET 2026 · 15 MAY · SHIFT 1Medium

Vector (Cross) Product

If ∣A⃗×B⃗∣=3(A⃗⋅B⃗)|\vec{A} \times \vec{B}| = \sqrt{3}(\vec{A} \cdot \vec{B}) then the value of ∣A⃗+B⃗∣|\vec{A} + \vec{B}| is (tan⁡60∘=3cos⁡60∘=12\tan 60^\circ = \sqrt{3} \quad \cos 60^\circ = \frac{1}{2})

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Answer: (d)

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Q3MHT CET 2026 · 19 APR · SHIFT 1Medium

Vector (Cross) Product

For two vectors P⃗\vec{P} and Q⃗P⃗⋅Q⃗=∣P⃗×Q⃗∣\vec{Q} \quad \vec{P} \cdot \vec{Q} = |\vec{P} \times \vec{Q}|

The magnitude of R⃗=P⃗+Q⃗\vec{R} = \vec{P} + \vec{Q} is (cos⁡45∘=12\cos 45^\circ = \frac{1}{\sqrt{2}})?

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Answer: (d)

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Q4MHT CET 2025 · 26 APR · SHIFT 1Easy

Vector (Cross) Product

If ∣a⃗∣=26, ∣b⃗∣=7|\vec{a}| = \sqrt{26}, \ |\vec{b}| = 7

∣a⃗×b⃗∣=35|\vec{a} \times \vec{b}| = 35, find a⃗⋅b⃗\vec{a} \cdot \vec{b}

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Answer: (d)

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Q5MHT CET 2025 · 25 APR · SHIFT 1Easy

Vector (Cross) Product

Vector A⃗\vec{A} of magnitude 535\sqrt{3} units, another vector B⃗\vec{B} of magnitude of 10 units are inclined to each other at an angle of 30∘30^\circ. The magnitude of vector product of the two vectors is [sin⁡30∘=12]\left[\sin 30^\circ = \frac{1}{2}\right]

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Answer: (c)

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Q6MHT CET 2025 · 20 APR · SHIFT 1Medium

Vector (Cross) Product

If A⃗=i^+j^+3k^, B⃗=−i^+j^+4k^\vec{A} = \hat{i} + \hat{j} + 3\hat{k}, \ \vec{B} = -\hat{i} + \hat{j} + 4\hat{k} and C⃗=2i^−2j^−8k^\vec{C} = 2\hat{i} - 2\hat{j} - 8\hat{k}, then the angle between the vectors P⃗=A⃗+B⃗+C⃗\vec{P} = \vec{A} + \vec{B} + \vec{C} and Q⃗=(A⃗×B⃗)\vec{Q} = (\vec{A} \times \vec{B}) is (in degree)

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Answer: (c)

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Q7JEE Main 2024 · 6 APR · SHIFT 1Medium

Vector (Cross) Product

For three vectors A⃗=(−xi^−6j^−2k^), B⃗=(−i^+4j^+3k^)\vec{A} = (-x\hat{i} - 6\hat{j} - 2\hat{k}), \ \vec{B} = (-\hat{i} + 4\hat{j} + 3\hat{k}) and C⃗=(−8i^−j^+3k^)\vec{C} = (-8\hat{i} - \hat{j} + 3\hat{k}), if A⃗⋅(B⃗×C⃗)=0\vec{A} \cdot (\vec{B} \times \vec{C}) = 0, then value of xx is ________.

Numerical answer type. Work it out, then open the answer.

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Answer: 4

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Q8JEE Main 2023 · 25 JAN · SHIFT 1Medium

Vector (Cross) Product

If P⃗=3i^+3j^+2k^\vec{P} = 3\hat{i} + \sqrt{3}\hat{j} + 2\hat{k} and Q⃗=4i^+3j^+2.5k^\vec{Q} = 4\hat{i} + \sqrt{3}\hat{j} + 2.5\hat{k} then, the unit vector in the direction of P⃗×Q⃗\vec{P} \times \vec{Q}is 1x(3i^+j^−23k^)\frac{1}{x}\left(\sqrt{3}\hat{i} + \hat{j} - 2\sqrt{3}\hat{k}\right). The value of xx is _________.

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Answer: 4

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Q9NEET 2022 · PHASE 2Easy

Vector (Cross) Product

If F⃗=2i^+j^−k^\vec{F} = 2\hat{i} + \hat{j} - \hat{k} andr⃗=3i^+2j^−2k^\vec{r} = 3\hat{i} + 2\hat{j} - 2\hat{k}, then the scalar and vector products of F⃗\vec{F}andr⃗\vec{r}have the magnitudes respectively as

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Answer: (d)

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Q10JEE Main 2022 · 25 JUN · SHIFT 1Easy

Vector (Cross) Product

A⃗\vec{A}is a vector quantity such that ∣A⃗∣|\vec{A}| = non-zero constant. Which of the following expression is true for A⃗\vec{A}?

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Answer: (c)

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Q11JEE Main 2021 · 25 FEB · SHIFT 2Easy

Vector (Cross) Product

If P⃗×Q⃗=Q⃗×P⃗\vec{P} \times \vec{Q} = \vec{Q} \times \vec{P}, the angle between P⃗\vec{P}and Q⃗\vec{Q} is θ(0∘\theta(0^\circ < θ\theta < 360∘^\circ). The value of 'θ\theta' will be ___________∘^\circ.

Numerical answer type. Work it out, then open the answer.

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Answer: 180

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Q12JEE Main 2021 · 20 JUL · SHIFT 1Medium

Vector (Cross) Product

If A⃗\vec{A}and B⃗\vec{B} are two vectors satisfying the relation A⃗B⃗\vec{A} \quad \vec{B}. = Figure. Then the value of Figure will be:

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Answer: (c)

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Q13JEE Main 2021 · 22 JUL · SHIFT 2Difficult

Vector (Cross) Product

Three particles P, Q and R are moving along the vectors A⃗=i^+j^B⃗=j^+k^\vec{A} = \hat{i} + \hat{j} \quad \vec{B} = \hat{j} + \hat{k} and C⃗=−i^+j^\vec{C} = -\hat{i} + \hat{j} respectively. They strike on a point and start to move in different directions. Now particle P is moving normal to the plane which contains vector A⃗\vec{A}and B⃗\vec{B}. Similarly particle Q is moving normal to the plane which contains vector A⃗\vec{A}and C⃗\vec{C}. The angle between the direction of motion of P and Q is cos⁡−1(1x)\cos^{-1}\left(\frac{1}{\sqrt{x}}\right). Then the value of x is _______________.

Numerical answer type. Work it out, then open the answer.

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Answer: 3

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Q14MHT CET 2020 · 19 OCT · SHIFT 2Easy

Vector (Cross) Product

What is the angle between resultant of A+BA + B and A×B\mathbf{A} \times \mathbf{B}.

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Answer: (d)

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Q15JEE Main 2004 · AIEEEEasy

Vector (Cross) Product

If A⃗×B⃗=B⃗×A⃗\vec{A} \times \vec{B} = \vec{B} \times \vec{A}, then the angle between A and B is

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Answer: (c)

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Q16NEET 1999 · AIPMTMedium

Vector (Cross) Product

What is the linear velocity if angular velocity vector ω⃗=3i^−4j^+k^\vec{\omega} = 3\hat{i} - 4\hat{j} + \hat{k} and position vector r⃗=5i^−6j^+6k^\vec{r} = 5\hat{i} - 6\hat{j} + 6\hat{k}?

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Answer: (b)

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