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Theory · Physics Circle Master Book

Surface Tension

01
CONCEPT

Molecular Theory & Factors

In one line
Surface molecules feel a net inward pull, so the surface behaves like a stretched membrane trying to shrink.
INTERMOLECULAR

3.1.1 Intermolecular forces

CohesiveAdhesive
same substancedifferent substances
two drops merge into onewater wets glass
  1. Their origin is electromagnetic. They do not obey the inverse square law.
SURFACE TENSION

3.1.2 What is surface tension?

line L
Force on either side of a line on the surface
T = FL
  1. Force per unit length on either side of an imaginary line, along the surface and at right angles to the line.
  2. Unit: N m⁻¹, dyne cm⁻¹. Dimensions: [MT⁻²].
  3. A scalar, independent of the area of the surface.
  4. A small drop is spherical: least area for a given volume.
MOLECULES

3.1.3 Molecular theory

ABCDfilm
Each circle is a sphere of influence
  1. Molecular range: the largest distance of attraction, about 10⁻⁹ m.
  2. Sphere of influence: sphere of that radius around a molecule.
  3. A, B (deep): pulled equally on all sides, net force zero.
  4. C (in the film): net downward force.
  5. D (on the surface): maximum downward force.
  6. Surface molecules have maximum potential energy, so the surface tends to shrink.
TEMPERATURE

3.1.4 Effect of temperature

Tt = T₀(1 − αt)
  1. T falls as temperature rises. Exception: molten copper and cadmium.
  2. At the critical temperature, T = 0.
  3. Hot soup tastes better.
IMPURITIES

3.1.5 Effect of impurities

AddedT
highly soluble (NaCl)increases
sparingly soluble (phenol)decreases
insoluble, soap, detergentdecreases
USES

3.1.6 Everyday uses

  1. Soap lowers T of water: clothes clean easily, spraying is easier.
  2. Water does not wet grease: the angle of contact is obtuse.
Practise PYQs on this topicMolecular Theory & Factors · 15 questions with solutions
02
CONCEPT

Force due to Surface Tension

In one line
Force = T × total length of contact with the liquid. Count both sides wherever the liquid touches both.
RULE

3.2.1 Force needed to lift a body

F = T × (length of contact) + W
BodyForce
needle or wire, length l2lT + W
thin ring, radius r4πrT + W
hollow disc, r₁ and r₂2π(r₁ + r₂)T + W
circular plate, radius r2πrT + W
square frame, side l8lT + W
square plate, side l4lT + W
F
Lifting a ring out of the liquid
FLOATING

3.2.2 Floating needle, wire or coin

mgTT
Vertical parts of T balance the weight
  1. A greased needle floats on water without breaking the surface.
  2. Wire of length L: πr²Ldg = 2LT.
rmax = √(2Tπdg)
  1. Coin of radius r, thickness t: πr²tρg = 2πrT.
rmax = 2Tρgt
  1. Disc with surface bent at θ to its edge: Weight = upthrust + 2πrT cos θ.
FILM

3.2.3 Soap film on a frame

  1. A film has two surfaces.
  2. Slider of length l supporting W: W = 2lT.
  3. A thread loop on a film turns circular when the film inside it is pierced.
TUBE

3.2.4 Drop from a tube

Wdrop = 2πrT
PLATES

3.2.5 Water film between two plates

tF
Plates are hard to pull apart
F = 2ATt = 2A²TV
  1. t is the film thickness; volume V = At.
HALF DROP

3.2.6 Drop half immersed

WU + 2πrTdρ
Weight = upthrust + surface tension force
43πr³ρg = 23πr³dg + 2πrT
r² = 3T(2ρ − d)g
Practise PYQs on this topicForce due to Surface Tension · 22 questions with solutions
03
CONCEPT

Surface Energy & Work Done

In one line
Surface tension is also the energy per unit area of a surface. New surface costs work.
ENERGY

3.3.1 Surface energy

  1. Bringing a molecule to the surface needs work, stored as potential energy.
  2. Potential energy per unit area of surface is surface energy.
  3. Unit: J m⁻². Dimensions: [MT⁻²].
FILM

3.3.2 Work on a soap film

FlT × 2lx
Sliding wire pulled through x
  1. Force on the wire: F = T × 2l.
  2. Moved through x: area grows by 2lx on the two sides together.
W = T × ΔA  (film: ΔA = 2 × change in area)
T = WΔA
  1. So surface tension is work done per unit area.
  2. Film expanded from A₁ to A₂: W = 2T(A₂ − A₁).
  3. Two wires of length l, gap raised by d: W = 2Tld.
  4. At constant T, energy is proportional to area.
BLOWING

3.3.3 Blowing a drop or bubble

BodySurfacesWork, r₁ to r₂
dropone4πT(r₂² − r₁²)
soap bubbletwo8πT(r₂² − r₁²)
New bubble: W = 8πr²T
  1. In terms of diameter: W = 2πT(D² − d²).
  2. W ∝ r² ∝ V2/3.
  3. Hotter solution has smaller T, so the work is a little less.
Practise PYQs on this topicSurface Energy & Work Done · 30 questions with solutions
04
CONCEPT

Splitting & Merging of Drops

In one line
Volume stays the same, area changes. Splitting needs energy; merging releases it.
SPLITTING

3.4.1 Splitting a drop

Rn drops, radius r
One drop becomes n equal drops
43πR³ = n43πr³  ⇒  R³ = nr³  ⇒  R = n1/3 r
  1. Work = T × (final area − initial area). All these forms are equal:
W = 4πT(nr² − R²)
W = 4πR²T(n1/3 − 1)
W = 4πTr²n2/3(n1/3 − 1)
W = 4πTR³(1r − 1R)
  1. Quick count: 8 drops: n1/3 = 2. 27: 3. 64: 4. 125: 5. 512: 8. 729: 9. 1000: 10.
RATIO

3.4.2 Ratio of surface energies

E of n small dropsE of big drop = n1/3
  1. Sprayed into n drops: the energy becomes n1/3 times.
  2. One big drop to one small drop: n2/3 : 1.
  3. Spraying without outside work cools the liquid.
MERGING

3.4.3 Merging into a big drop

  1. Area falls, so energy is released.
E = 4πr²T(n − n2/3) = 4πR²T(n1/3 − 1)
  1. If surface energy of each drop is E, released energy = E(n − n2/3).
  2. In terms of volume V: E = 3VT(1r − 1R).
USE

3.4.4 Where the energy goes

Used asResult
heat in the big dropΔθ = 3TJSd(1r − 1R)
kinetic energyv = √(6Td(1r − 1R))
  1. J = mechanical equivalent of heat, S = specific heat, d = density.
Practise PYQs on this topicSplitting & Merging of Drops · 54 questions with solutions
05
CONCEPT

Excess Pressure: Drops & Bubbles

In one line
Pressure on the concave side of a curved surface is larger. The smaller the radius, the larger the excess.
RULES

3.5.1 Excess pressure in different cases

Drop
Bubble in air
Bubble in liquid
h
Bubble at depth h
SurfaceΔP
plane0
drop, or bubble in a liquid2TR
soap bubble in air4TR
bubble at depth h in liquid2TR + hρg
cylindricalTR
unequal radii, one surfaceT(1R₁ + 1R₂)
  1. A soap bubble has two surfaces, so it has twice the excess of a drop.
  2. Absolute pressure inside: P = P₀ + ΔP.
RATIOS

3.5.2 Quick ratios

ΔP ∝ 1r  ⇒  r₁r₂ = ΔP₂ΔP₁
  1. V ∝ r³ and m ∝ r³: three times the excess gives 1 : 27 in volume.
  2. Blow air in: r grows, so the pressure inside falls.
  3. n drops merged: R = n1/3r, so ΔP becomes 1n1/3 times.
CONNECTED

3.5.3 Two connected bubbles

P₁P₂P₁ > P₂
Air flows from the small bubble to the large one
  1. Smaller bubble has higher pressure.
  2. Air flows until the small bubble shrinks to a droplet.
INSIDE

3.5.4 Bubble inside a bubble

P₂ − P₀ = 4Tr₁ + 4Tr₂
Equivalent: 1r = 1r₁ + 1r₂
MERGING

3.5.5 Two bubbles combine

abc
Isothermal: PV adds up
PaVa + PbVb = PcVc
T = P₀(c³ − a³ − b³)4(a² + b² − c²)
In vacuum: c² = a² + b²
  1. Common surface of two bubbles in contact has radius below.
r = abb − a
  1. Mercury drops merging (no air inside) just keep their volume: R³ = R₁³ + R₂³.
JEE · NEET

Corner

Double bubble
r₂r₁
Interface bends towards the larger bubble
  1. Inner surface: excess pressure runs from the concave to the convex side.
1r = 1r₁ − 1r₂  ⇒  r = r₁r₂r₂ − r₁
Charged soap bubble
  1. Charging pushes the surface outward, so the bubble grows.
Practise PYQs on this topicExcess Pressure: Drops & Bubbles · 60 questions with solutions
06
CONCEPT

Angle of Contact & Capillarity

In one line
The liquid rises in a narrow tube if it wets the tube, and the narrower the tube, the higher it rises.
ANGLE

3.6.1 Angle of contact

θ < 90°θ = 90°θ > 90°
Angle measured inside the liquid
θMeniscusWets?Level
below 90°concaveyesrises
90°planenono change
above 90°convexnofalls
  1. Angle between the tangents to the liquid and to the solid, inside the liquid.
  2. θ = 0° pure water and glass; 90° water and silver; 138° mercury and glass.
  3. It depends on the pair of liquid and solid, not on the inclination of the wall.
  4. It decreases on heating.
  5. Wax coating raises θ: this is water proofing.
water, glasswater, silvermercury, glass
Three common pairs
CAPILLARITY

3.6.2 Capillary rise

hP − 2T/RP
Liquid column balances the pressure drop
  1. Pressure just below the meniscus is lower by 2TR.
  2. R = rcos θ.
hρg = 2TR
h = 2T cos θrρg
  1. Examples: ink in blotting paper, oil in a wick, towel soaking water.
  2. With the meniscus included: h + r3.
JURIN

3.6.3 Jurin’s law

hr = constant
  1. Area a times: radius √a times.
  2. For different liquids: h ∝ T cos θρ.
  3. Same h with same T, r: cos θ ∝ ρ.
  4. h does not depend on the shape of the tube.
Same meniscus radius, same height
SHORT

3.6.4 Tube shorter than h

hLr′ > r
No overflow: the meniscus flattens
hr = Lr′
  1. Liquid reaches the top and stays; it never overflows.
  2. Apparent angle: cos θ′ = Lh.
TILTED

3.6.5 Tilted tube

hlα
Vertical height stays the same
l = hcos α
COLUMN

3.6.6 Mass and force of the column

  1. Upward force = T cos θ × 2πr = weight of the column.
  2. m = πr²hρ. As hr is constant, m ∝ r.
GRAVITY

3.6.7 Changing g

  1. h ∝ 1g.
  2. Moon: 6 times. Mine: g′ = g(1 − dR).
  3. Lift going up: g + a, h falls. Going down: g − a, h rises.
  4. Free fall or satellite: g = 0, water fills the tube to its top.
U-TUBE

3.6.8 U-tube of unequal bores

hr₁r₂
Narrow limb stands higher
h = 2T cos θρg(1r₁ − 1r₂)
JEE · NEET

Corner

Shape of drops
liquidairsolidTSATSLTLAθ
Three surface tensions meet at the edge
TSL + TLA cos θ = TSA  ⇒  cos θ = TSA − TSLTLA
  1. TSA > TSL: θ acute (water on glass).
  2. TSA < TSL: θ obtuse (mercury on glass, water on lotus leaf).
  3. TSL + TLA cos θ < TSA: the liquid spreads.
Force behind the meniscus
Fₐ
Fc < √2 Fa: concave
Fₐ
Fc = √2 Fa: plane
Fₐ
Fc > √2 Fa: convex
Fa acts along the normal to the wall, Fc at 45° to the vertical
tan α = Fc√2 Fa − Fc
  1. The free surface stands at right angles to the resultant.
Practise PYQs on this topicAngle of Contact & Capillarity · 70 questions with solutions
EXAM-DAY CARD

Just see this before the exam

Surface Tension
T = FL
definition
W = T ΔA
energy
W = 4πR²T(n1/3 − 1)
splitting
ΔP = 4TR
bubble
h = 2T cos θrρg
capillary
hr = constant
Jurin
FORMULA SHEET

Whole chapter on one page

Basics

T = FL = WΔA

Tt = T₀(1 − αt)

[T] = MT⁻²

Force

ring 4πrT, plate 2πrT

frame 8lT, wire 2lT

plates: F = 2ATt

Work

film: 2T ΔA

drop: 4πT(r₂² − r₁²)

bubble: 8πT(r₂² − r₁²)

Drops

R = n1/3 r

W = 4πR²T(n1/3 − 1)

EsmallEbig = n1/3

Excess pressure

drop 2TR, bubble 4TR

c² = a² + b² (vacuum)

r = abb − a

Capillary

h = 2T cos θrρg

hr = constant, h ∝ 1g

m ∝ r, l = hcos α

TOP MISTAKES

Avoid these = easy marks

MISTAKE ✗

Film or bubble with one surface

Drop excess pressure as 4TR

Area halved means h doubled

Short tube overflows

CORRECT ✓

Film and bubble: two surfaces

Drop 2TR, bubble 4TR

h ∝ 1r, and area ∝ r²

Rises to the top, no overflow