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Work, Energy and Power PYQs · MHT CET · JEE Main · NEET

Power

Questions
51
MHT CET
8
JEE Main
25
NEET
18
Years
1990–2026
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Q1NEET 2026Easy

Power · Average power: P = W/t

The power of a crane, which lifts a mass of 1000 kg to a height of 20 m in 10 s is: (g=9.8 m/s2)\left(g = 9.8\text{ m/s}^2\right)

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Answer: (c)

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Q2MHT CET 2026 · 19 MAY · SHIFT 2Easy

Power · Constant power: how v and s grow with t

A body is moved along a straight line by a machine delivering constant power. The distance moved by the body in time tt is proportional to

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Answer: (c)

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Q3MHT CET 2026 · 16 APR · SHIFT 2Medium

Power · Power from a force F(t)

A body of mass 1kg begins to move under the action of a time dependent force F⃗=(ti^+3t2j^)\vec{F} = (t\hat{i} + 3t^2\hat{j}) N where i^\hat{i} and j^\hat{j} are the unit vectors along x and y axis. The power developed by the above force at time t=2t = 2 s will be (in watt)

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Answer: (a)

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Q4JEE Main 2026 · 4 APR · SHIFT 1Medium

Power · Power from a force F(t)

A body of mass 2 kg begins to move under the influence of time dependent force F⃗=(2ti^+6t2j^) N\vec{F} = \left(2t\hat{i} + 6t^2\hat{j}\right)\text{ N}, where i^\hat{i} and j^\hat{j} are unit vectors along xx and y -axis respectively. The power produced by the force at t=2 st = 2\text{ s} is ______ W.

Numerical answer type. Work it out, then open the answer.

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Answer: 200

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Q5MHT CET 2026 · 15 MAY · SHIFT 2Medium

Power · Constant power: how v and s grow with t

If the force acting on a body is inversely proportional to its speed, the kinetic energy of the body is

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Answer: (b)

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Q6MHT CET 2025 · 25 APR · SHIFT 2Easy

Power · Average power: P = W/t

A constant force F⃗=3i^−2j^−k^\vec{F} = 3\hat{i} - 2\hat{j} - \hat{k} newton has a displacement r⃗=2i^−3j^−3k^\vec{r} = 2\hat{i} - 3\hat{j} - 3\hat{k} metre in 2 second. The work done and the power are respectively

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Answer: (b)

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Q7JEE Main 2025 · 28 JAN · SHIFT 2Medium

Power · Average power: P = W/t

A body of mass 4 kg is placed on a plane at a point PP having coordinates (3,4) m(3, 4)\text{ m}. Under the action of forceF⃗=(2i^+3j^) N\vec{F} = (2\hat{i} + 3\hat{j})\text{ N}, it moves to a new point Q having coordinates (6,10) m(6, 10)\text{ m} in 4 sec. The average power and instantaneous power at the end of 4 sec are in the ratio of:

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Answer: (d)

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Q8MHT CET 2025 · 22 APR · SHIFT 1Medium

Power · Power from a force F(t)

A body of mass 1 kg begins to move under the action of a time dependent force F⃗=(ti^+2t2j^) N\vec{F} = \left(t\hat{i} + 2t^2\hat{j}\right)\text{ N}, where i^\hat{i} and j^\hat{j} are unit vectors along xx and yy axis. The power developed by above force at time t=3t = 3 second will be

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Answer: (a)

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Q9JEE Main 2025 · 7 APR · SHIFT 1Medium

Power · Power from a force F(t)

An object of mass 1000 g experiences a time dependent force F⃗=(2ti^+3t2j^)N\vec{F} = \left(2t\hat{i} + 3t^2\hat{j}\right)N. The power generated by the force at time tt is:

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Answer: (c)

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Q10JEE Main 2025 · 29 JAN · SHIFT 2Difficult

Power · Conveyors, jets & wind

A sand dropper drops sand of mass m(t) on a conveyer belt at a rate proportional to the square root of speed (v) of the belt, i.e., dmdt∝v\frac{dm}{dt} \propto \sqrt{v}. If P is the power delivered to run the belt at constant speed then which of the following relationship is true?

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Answer: (d)

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Q11MHT CET 2024 · 15 MAY · SHIFT 1Easy

Power · Average power: P = W/t

A body of mass 1 kg starts from rest and moves with uniform acceleration. In 2 seconds, its velocity is 10 m/s10\text{ m/s}. The power exerted on the body in one second is

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Answer: (b)

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Q12NEET 2024Easy

Power · Instantaneous power: P = F·v

At any instant of time tt, the displacement of any particle is given by 2t−12t - 1 (SI\text{SI} unit) under the influence of force of 5 N5\text{ N}. The value of instantaneous power is (in SI\text{SI} unit):

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Answer: (a)

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Q13JEE Main 2024 · 5 APR · SHIFT 2Easy

Power · Constant power: how v and s grow with t

A body is moving unidirectionally under the influence of a constant power source. Its displacement in time t is proportional to:

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Answer: (b)

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Q14MHT CET 2024 · 16 MAY · SHIFT 1Medium

Power · Instantaneous power: P = F·v

The power (P)(P) is supplied to a rotating body having moment of inertia ' I ' and angular acceleration ' α\alpha '. Its instantaneous angular velocity ' ω\omega ' is

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Answer: (a)

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Q15JEE Main 2024 · 31 JAN · SHIFT 2Medium

Power · Power from a force F(t)

A body of mass 2 kg2\text{ kg} begins to move under the action of a time dependent force given by F⃗=(6ti^+6t2j^)N\vec{F} = \left(6t\hat{i} + 6t^2\hat{j}\right)N. The power developed by the force at the time tt is given by:

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Answer: (d)

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Q16NEET 2023Easy

Power · Instantaneous power: P = F·v

A particle moves with a velocity (5i^−3j^+6k^) m s−1(5\hat{i} - 3\hat{j} + 6\hat{k})\text{ m s}^{-1} horizontally under the action of constant force (10i^+10j^+20k^) N(10\hat{i} + 10\hat{j} + 20\hat{k})\text{ N}. The instantaneous power supplied to the particle is:

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Answer: (d)

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Q17JEE Main 2023 · 13 APR · SHIFT 1Medium

Power · Average power: P = W/t

The ratio of powers of two motors is 3xx+1\frac{3\sqrt{x}}{\sqrt{x} + 1}, that are capable of raising 300 kg300\text{ kg} water in 5 minutes and 50 kg50\text{ kg} water in 2 minutes respectively from a well of 100 m100\text{ m} deep. The value of xx will be

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Answer: (a)

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Q18JEE Main 2023 · 11 APR · SHIFT 2Medium

Power · Instantaneous power: P = F·v

A block of mass 5 kg5\text{ kg} starting from rest is pulled up on a smooth inclined plane making an angle of 30∘30^\circ with horizontal with an effective acceleration of 1 m s−21\text{ m s}^{-2}. The power delivered by the pulling force at t=10 st = 10\text{ s} from the start is ___________ W.

[use g=10 m s−2g = 10\text{ m s}^{-2} ]

(calculate the nearest integer value)

Numerical answer type. Work it out, then open the answer.

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Answer: 300

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Q19JEE Main 2023 · 24 JAN · SHIFT 2Medium

Power · Power from a force F(t)

A body of mass 1kg begins to move under the action of a time dependent force F⃗=(ti^+3t2j^)\vec{F} = \left(t\hat{i} + 3t^2\hat{j}\right) N, where i^\hat{i} and j^\hat{j} are the unit vectors along xx and yy axis. The power developed by above force, at the time t = 2s, will be ____________ W.

Numerical answer type. Work it out, then open the answer.

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Answer: 100

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Q20JEE Main 2023 · 10 APR · SHIFT 2Medium

Power · Lifts & vehicles against friction

If the maximum load carried by an elevator is 1400 kg1400\text{ kg} ( 600 kg600\text{ kg} - Passengers + 800 kg\text{kg} - elevator), which is moving up with a uniform speed of 3 m s−13\text{ m s}^{-1} and the frictional force acting on it is 2000 N2000\text{ N}, then the maximum power used by the motor is __________ kW (g=10 m/s2)\text{kW}\ \left(g = 10\text{ m/s}^2\right)

Numerical answer type. Work it out, then open the answer.

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Answer: 48

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Q21JEE Main 2023 · 30 JAN · SHIFT 2Medium

Power · Constant power: how v and s grow with t

A body of mass 2 kg2\text{ kg} is initially at rest. It starts moving unidirectionally under the influence of a source of constant power P. Its displacement in 4 s4\text{ s} is 13α2P m\frac{1}{3}\alpha^2\sqrt{P}\text{ m}. The value of α\alpha will be ______.

Numerical answer type. Work it out, then open the answer.

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Answer: 4

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Q22NEET 2022 · PHASE 1Easy

Power · Average power: P = W/t

The energy that will be ideally radiated by a 100 kW transmitter in 1 hour is

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Answer: (a)

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Q23NEET 2022 · PHASE 1Medium

Power · Lifts & vehicles against friction

An electric lift with a maximum load of 2000 kg (lift + passengers) is moving up with a constant speed of 1.5 ms−1{}^{-1}. The frictional force opposing the motion is 3000 N. The minimum power delivered by the motor to the lift in watts is: (g = 10 ms−2{}^{-2})

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Answer: (c)

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Q24JEE Main 2022 · 27 JUL · SHIFT 1Medium

Power · Conveyors, jets & wind

Sand is being dropped from a stationary dropper at a rate of 0.5 kg s−10.5\text{ kg s}^{-1} on a conveyor belt moving with a velocity of 5 m s−15\text{ m s}^{-1}. The power needed to keep the belt moving with the same velocity will be:

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Answer: (d)

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Q25NEET 2021Easy

Power · Average power: P = W/t

Water falls from a height of 60m at the rate of 15 kg/s to operate a turbine. The losses due to frictional force are 10% of the input energy. How much power is generated by the turbine? (g = 10 m/s2)

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Answer: (c)

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Q26JEE Main 2021 · 20 JUL · SHIFT 2Easy

Power · Constant power: how v and s grow with t

A body at rest is moved along a horizontal straight line by a machine delivering a constant power. The distance moved by the body in time 't' is proportional to:

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Answer: (a)

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Q27JEE Main 2021 · 18 MAR · SHIFT 1Easy

Power · Constant power: how v and s grow with t

A constant power delivering machine has towed a box, which was initially at rest, along a horizontal straight line. The distance moved by the box in time 't' is proportional to :-

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Answer: (b)

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Q28MHT CET 2021 · 22 SEP · SHIFT 1Medium

Power · Average power: P = W/t

A car of mass 'mm' moving with velocity 'uu' on a straight road in a straight line, doubles its velocity in time t. The power delivered by the engine of a car for doubling the velocity is

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Answer: (a)

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Q29JEE Main 2021 · 27 JUL · SHIFT 2Medium

Power · Constant power: how v and s grow with t

An automobile of mass 'm' accelerates starting from origin and initially at rest, while the engine supplies constant power P. The position is given as a function of time by:

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Answer: (d)

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Q30JEE Main 2020 · 3 SEP · SHIFT 2Easy

Power · Constant power: how v and s grow with t

A particle is moving unidirectionally on a horizontal plane under the action of a constant power supplying energy source. The displacement (s) - time (t) graph that describes the motion of the particle is (graphs are drawn schematically and are not to scale):

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Answer: (b)

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Q31JEE Main 2020 · 7 JAN · SHIFT 2Medium

Power · Lifts & vehicles against friction

An elevator in a building can carry a maximum of 10 persons, with the average mass of each person being 68 kg. The mass of the elevator itself is 920 kg and it moves with a constant speed of 3 m/s. The frictional force opposing the motion is 6000 N. If the elevator is moving up with its full capacity, the power delivered by the motor to the elevator (g = 10 m/s2) must be at least:

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Answer: (d)

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Q32JEE Main 2020 · 7 JAN · SHIFT 1Medium

Power · Lifts & vehicles against friction

A 60 HP electric motor lifts an elevator having a maximum total load capacity of 2000 kg. If the frictional force on the elevator is 4000 N, the speed of the elevator at full load is close to: (1 HP = 746 W, g = 10 ms-2)

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Answer: (d)

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Q33JEE Main 2020 · 5 SEP · SHIFT 2Medium

Power · Constant power: how v and s grow with t

A body of mass 2 kg is driven by an engine delivering a constant power of 1 J/s. The body starts from rest and moves in a straight line. After 9 seconds, the body has moved a distance (in m) _______.

Numerical answer type. Work it out, then open the answer.

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Answer: 18

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Q34NEET 2016 · PHASE 1Medium

Power · Power from a force F(t)

A body of mass 1 kg begins to move under the action of a time dependent force F⃗=(2ti^+3t2j^)N,\vec{F} = \left(2t\hat{i} + 3t^2\hat{j}\right)N, where i^\hat{i} and j^\hat{j} are unit vectors along x and y axis. What power will be developed by the force at the time t?

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Answer: (b)

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Q35JEE Main 2016 · 9 APR · SHIFT 1Difficult

Power · Lifts & vehicles against friction

A car of weight W is on an inclined road that rises by 100 m over a distance of 1 km and applies a constant frictional force W20\frac{W}{20} on the car. While moving uphill on the road at a speed of 10 ms−1, the car needs power P. If it needs power P2\frac{P}{2} while moving downhill at speed v then value of vv is:

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Answer: (b)

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Q36NEET 2015 · AIPMTMedium

Power · Average power: P = W/t

The heart of a man pumps 5 litres of blood through the arteries per minute at a pressure of 150 mm of mercury. If the density of mercury be 13.6 ×\times 103 kg/m3 and g = 10 m/s2 then the power (in watt) is

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Answer: (c)

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Q37NEET 2015 · AIPMT · CANCELLED PAPERMedium

Power · Constant power: how v and s grow with t

A particle of mass m is driven by a machine that delivers a constant power k watts. If the particle starts from rest the force on the particle at time t is

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Answer: (c)

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Q38NEET 2013Easy

Power · Average power: P = W/t

One coolie takes 1 minute to raise a suitcase through a height of 2 m but the second coolie takes 30 s to raise the same suitcase to the same height. The powers of two coolies are in the ratio

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Answer: (d)

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Q39JEE Main 2013 · 25 APR · SHIFT 1Easy

Power · Conveyors, jets & wind

A wind-powered generator converts wind energy into electrical energy. Assume that the generator converts a fixed fraction of the wind energy intercepted by its blades into electrical energy. For wind speed vv, the electrical power output will be most likely proportional to

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Answer: (d)

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Q40JEE Main 2013 · 23 APR · SHIFT 1Difficult

Power · Instantaneous power: P = F·v

A 70 kg man leaps vertically into the air from a crouching position. To take the leap the man pushes the ground with a constant force F to raise himself. The center of gravity rises by 0.5 m before he leaps. After the leap the c.g. rises by another 1 m. The maximum power delivered by the muscles is: (Take g = 10 ms−2-2)

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Answer: (b)

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Q41NEET 2012 · AIPMT · MAINSEasy

Power · Constant power: how v and s grow with t

A car of mass m starts from rest and accelerates so that the instantaneous power delivered to the car has a constant magnitude P0. The instantaneous velocity of this car is proportional to

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Answer: (b)

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Q42NEET 2011 · AIPMT · PRELIMSMedium

Power · Instantaneous power: P = F·v

A body projected vertically from the earth reaches a height equal to earth's radius before returning to the earth. The power exerted by the gravitational force is greatest

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Answer: (b)

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Q43NEET 2010 · AIPMT · MAINSMedium

Power · Instantaneous power: P = F·v

A particle of mass M, starting from rest, undergoes uniform acceleration. If the speed acquired in time T is V, the power delivered to the particle is

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Answer: (d)

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Q44NEET 2010 · AIPMT · PRELIMSMedium

Power · Conveyors, jets & wind

An engine pumps water through a hose pipe. Water passes through the pipe and leaves it with a velocity of 2 m/s. The mass per unit length of water in the pipe is 100 kg/m. What is the power of the engine?

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Answer: (a)

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Q45NEET 2009 · AIPMTMedium

Power · Conveyors, jets & wind

An engine pumps water continuously through a hose. Water leaves the hose with a velocity v and m is the mass per unit length of the water jet. What is the rate at which kinetic energy is imparted to water?

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Answer: (d)

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Q46NEET 2008 · AIPMTEasy

Power · Average power: P = W/t

Water falls from a height of 60 m at the rate of 15 kg/s to operate a turbine. The losses due to frictional forces are 10% of energy. How much power is generated by the turbine? (g = 10 m/s2)

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Answer: (c)

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Q47JEE Main 2005 · AIEEEEasy

Power · Instantaneous power: P = F·v

A body of mass mm is accelerated uniformly from rest to a speed vv in a time T.T. The instantaneous power delivered to the body as a function of time is given by

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Answer: (b)

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Q48JEE Main 2004 · AIEEEEasy

Power · Instantaneous power: P = F·v

A body of mass ’m’,\text{'}m\text{'}, accelerates uniformly from rest to ’v1’\text{'}v_1\text{'} in time TT. The instantaneous power delivered to the body as a function of time is given by

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Answer: (b)

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Q49JEE Main 2003 · AIEEEEasy

Power · Constant power: how v and s grow with t

A body is moved along a straight line by a machine delivering a constant power. The distance moved by the body in time ’t’\text{'}t\text{'} is proportional to

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Answer: (b)

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Q50NEET 2000 · AIPMTEasy

Power · Instantaneous power: P = F·v

If F⃗=(60i^+15j^−3k^)\vec{F} = \left(60\hat{i} + 15\hat{j} - 3\hat{k}\right) N andv⃗=(2i^−4j^+5k^)\vec{v} = \left(2\hat{i} - 4\hat{j} + 5\hat{k}\right) m/s, then instantaneous power is

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Answer: (b)

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Q51NEET 1990 · AIPMTEasy

Power · Average power: P = W/t

How much water a pump of 2 kW2\text{ kW} can raise in one minute to a height of 10 m10\text{ m}? (take g=10 m/s2g = 10\text{ m/s}^2)

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Answer: (b)

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