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Work, Energy and Power PYQs · MHT CET · JEE Main · NEET

Work by a Variable Force

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Q1NEET 2026 · RE-NEETMedium

Work by a Variable Force

A particle of mass MM moves along a horizontal xx axis from x=0x = 0 to x=Lx = L. The coefficient of kinetic friction varies as a function of xx as μk(x)=μ0−αx\mu_k(x) = \mu_0 - \alpha x, where μ0,α\mu_0, \alpha are constants of appropriate dimensions, so that μk(L)=0\mu_k(L) = 0. The total work done by the frictional force during the motion is nμ0MgLn\mu_0 MgL, where gg is the acceleration due to gravity. The value of nn is:

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Answer: (a)

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Q2JEE Main 2025 · 24 JAN · SHIFT 1Medium

Work by a Variable Force

A force F=α+βx2F = \alpha + \beta x^2 acts on an object in the x -direction. The work done by the force is 5 J when the object is displaced by 1 m. If the constant α=1 N\alpha = 1\text{ N} then β\beta will be

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Answer: (c)

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Q3JEE Main 2025 · 23 JAN · SHIFT 1Medium

Work by a Variable Force

A force f=x2yi^+y2j^f = x^2y\hat{i} + y^2\hat{j} acts on a particle in a plane x+y=10x + y = 10. The work done by this force during a displacement from (0,0)(0, 0) to (4 m,2 m)(4\text{ m}, 2\text{ m}) is _________ Joule (round off to the nearest integer)

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Answer: 152

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Q4NEET 2024Medium

Work by a Variable Force

An object moving along horizontal xx-direction with kinetic energy 10 J10\text{ J} is displaced through x=(3i^) mx = (3\hat{i})\text{ m} by the force F⃗=(−2i^+3j^) N\vec{F} = (-2\hat{i} + 3\hat{j})\text{ N}. The kinetic energy of the object at the end of the displacement xx is

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Answer: (c)

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Q5JEE Main 2023 · 11 APR · SHIFT 1Easy

Work by a Variable Force

A force F⃗=(2+3x)i^\vec{F} = (2 + 3x)\hat{i} acts on a particle in the xx direction where F is in newton and xx is in meter. The work done by this force during a displacement from x=0x = 0 to x=4 mx = 4\text{ m}, is __________ J.

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Answer: 32

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Q6JEE Main 2023 · 1 FEB · SHIFT 2Easy

Work by a Variable Force

A force F=(5+3y2)F = \left(5 + 3y^2\right) acts on a particle in the yy-direction, where FF is in newton and yy is in meter. The work done by the force during a displacement from y=2 my = 2\text{ m} to y=5 my = 5\text{ m} is ___________ J.

Numerical answer type. Work it out, then open the answer.

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Answer: 132

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Q7JEE Main 2023 · 15 APR · SHIFT 1Medium

Work by a Variable Force

A block of mass 10 kg10\text{ kg} is moving along xx-axis under the action of force F=5x NF = 5x\text{ N}. The work done by the force in moving the block from x=2 mx = 2\text{ m} to 4 m4\text{ m} will be __________ J.

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Answer: 30

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Q8JEE Main 2023 · 6 APR · SHIFT 1Medium

Work by a Variable Force

A particle of mass 10 g10\text{ g} moves in a straight line with retardation 2x2x, where xx is the displacement in SI units. Its loss of kinetic energy for above displacement is (10x)−n\left(\frac{10}{x}\right)^{-n} J. The value of nn will be __________

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Answer: 2

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Q9JEE Main 2023 · 25 JAN · SHIFT 1Difficult

Work by a Variable Force

An object of mass 'm' initially at rest on a smooth horizontal plane starts moving under the action of force F = 2N. In the process of its linear motion, the angle θ\theta (as shown in figure) between the direction of force and horizontal varies as θ=kx\theta = kx, where k is a constant and xx is the distance covered by the object from its initial position. The expression of kinetic energy of the object will be E=nksin⁡θE = \frac{n}{k}\sin\theta. The value of n is ___________.

Figure

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Answer: 2

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Q10JEE Main 2022 · 26 JUN · SHIFT 2Easy

Work by a Variable Force

Arrange the four graphs in descending order of total work done; where W1, W2, W3 and W4 are the work done corresponding to figure a, b, c and d respectively.

FigureFigure
FigureFigure
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Answer: (a)

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Q11JEE Main 2022 · 28 JUN · SHIFT 2Medium

Work by a Variable Force

A block of mass 2 kg moving on a horizontal surface with speed of 4 ms−1{}^{-1} enters a rough surface ranging from x = 0.5 m to x = 1.5 m. The retarding force in this range of rough surface is related to distance by F = −- kx where k = 12 Nm−1{}^{-1}. The speed of the block as it just crosses the rough surface will be:

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Answer: (c)

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Q12JEE Main 2022 · 24 JUN · SHIFT 1Medium

Work by a Variable Force

A particle experiences a variable force F⃗=(4xi^+3y2j^)\vec{F} = \left(4x\hat{i} + 3y^2\hat{j}\right) in a horizontal x-y plane. Assume distance in meters and force is newton. If the particle moves from point (1, 2) to point (2, 3) in the x-y plane, then Kinetic Energy changes by:

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Answer: (c)

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Q13JEE Main 2021 · 25 JUL · SHIFT 2Easy

Work by a Variable Force

A force of F = (5y + 20)j^\hat{j} N acts on a particle. The work done by this force when the particle is moved from y = 0 m to y = 10 m is ___________ J.

Numerical answer type. Work it out, then open the answer.

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Answer: 450

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Q14JEE Main 2020 · 4 SEP · SHIFT 2Medium

Work by a Variable Force

A person pushes a box on a rough horizontal platform surface. He applies a force of 200 N over a distance of 15 m. Thereafter, he gets progressively tired and his applied force reduces linearly with distance to 100 N. The total distance through which the box has been moved is 30 m. What is the work done by the person during the total movement of the box?

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Answer: (b)

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Q15JEE Main 2020 · 9 JAN · SHIFT 1Difficult

Work by a Variable Force

Consider a force F⃗=−xi^+yj^\vec{F} = -x\hat{i} + y\hat{j}. The work done by this force in moving a particle from point A(1, 0) to B(0, 1) along the line segment is: (all quantities are in SI units)

Figure

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Answer: (c)

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Q16NEET 2019Easy

Work by a Variable Force

A force F = 20 + 10y acts on a particle in y-direction where F is in newton and y in meter. Work done by this force to move the particle from y = 0 to y = 1 m is:

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Answer: (b)

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Q17NEET 2019Medium

Work by a Variable Force

An object of mass 500 g, initially at rest, is acted upon by a variable force whose X-component varies with X in the manner shown. The velocities of the object at the points X = 8 m and X = 12 m, would have the respective values of (nearly)

Figure

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Answer: (d)

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Q18JEE Main 2019 · 8 APR · SHIFT 1Medium

Work by a Variable Force

A particle moves in one dimension from rest under the influence of a force that varies with the distance travelled by the particle as shown in the figure. The kinetic energy of the particle after it has travelled 3m is:

Figure

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Answer: (a)

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Q19NEET 2015 · AIPMT · CANCELLED PAPEREasy

Work by a Variable Force

A block of mass 10 kg, moving in x direction with a constant speed of 10 m s−1{}^{-1}, is subjected to a retarding force F = 0.1x J/m during its travel from x = 20 m to 30 m. Its final KE will be

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Answer: (c)

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Q20JEE Main 2014Medium

Work by a Variable Force

When a rubber-band is stretched by a distance xx, it exerts restoring force of magnitude F=ax+bx2F = ax + bx^2 where aa and bb are constants. The work done in stretching the unstretched rubber-band by LL is:

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Answer: (c)

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Q21NEET 2011 · AIPMT · PRELIMSEasy

Work by a Variable Force

Force F on a particle moving in a straight line varies with distance d as shown in figure.

Figure

The work done on the particle during its displacement of 12 m is

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Answer: (d)

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Q22NEET 2005 · AIPMTEasy

Work by a Variable Force

A force F acting

Figure

on an object varies with distance x as shown here. The force is in N and x in m. The work done by the force in moving the object from x = 0 to x = 6 m is

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Answer: (b)

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Q23JEE Main 2004 · AIEEEMedium

Work by a Variable Force

A particle moves in a straight line with retardation proportional to its displacement. Its loss of kinetic energy for any displacement xx is proportional to

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Answer: (c)

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Q24NEET 1994 · AIPMTEasy

Work by a Variable Force

A body, constrained to move in yy-direction, is subjected to a force given by F⃗=(−2i^+15j^+6k^) N\vec{F} = (-2\hat{i} + 15\hat{j} + 6\hat{k})\text{ N}. The work done by this force in moving the body through a distance of 10j^ m10\hat{j}\text{ m} along yy-axis, is

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Answer: (a)

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Q25NEET 1994 · AIPMTEasy

Work by a Variable Force

A position dependent force, F=(7−2x+3x2) NF = (7 - 2x + 3x^2)\text{ N} acts on a small body of mass 2 kg2\text{ kg} and displaces it from x=0x = 0 to x=5 mx = 5\text{ m}. The work done in joule is

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Answer: (a)

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Q26NEET 1992 · AIPMTEasy

Work by a Variable Force

A position dependent force, F=(7−2x+3x2) NF = (7 - 2x + 3x^2)\text{ N} acts on a small body of mass 2 kg2\text{ kg} and displaces it from x=0x = 0 to x=5 mx = 5\text{ m}. The work done in joule is

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Answer: (a)

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